Answer:
97.35
Step-by-step explanation:
355.5 - 235.5 -22.65
I am subtracting 235.5 and 22.65 from 355.5 because I am spending that much money on the things.
=> 355.5 - 235.5 - 22.65
=> 120 - 22.65
=> 97.35 rupees
So, 97.35 rupees is left
Answer:
1 hour = 7/18 of the distance between two ports
Step-by-step explanation:
Given that:
In 3/7 hours distance traveled is 1/6
For finding distance in one hour, divide both sides by 7/3 so that 3/7 would be cancelled out:
3/7 * 7/3 hours = 1/6 * 7/3 distance
By simplifying:
1 hour = 7/18 of the distance between two ports
This means that in one hour 7/18 of the distance is covered between two ports.
i hope it will help you!
Answer:
Elena's sales and expenses will both be $
396
if she sells
36
boxes of cards.
Step-by-step explanation:
Answer: The first one is not a function the second is a function the third one is not one and the fourth one is
Step-by-step explanation:
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
