Q2 is the median, which is the middle number, which is 12
Q1 is the middle between the minimum and the median, which in this case is the middle between 6 and the second 12, which is both 9 and 10. so find the average (9+10/2) = 9.5
Q3 is the half way point between the median and the max, which is the second 12 and 24, 17 and 19 are the middle, once again find the average (17+19/2) which is 18
Q1: 9.2
Q2:12
Q3:18
Answer:
n/6
Step-by-step explanation:
If angle bisector of angle DBC is BE. What is m angle EBC, then <DBE = <EBC
Since <ABC = <ABD+<DBC
n = 2<DBC+<DBC
n = 3<DBC
<DBC = n/3
Since <DBC = 2EBC
n/3 = 2<EBC
n/6 = <EBC
Hence <EBC = n/6
Answer:
Let the length be l, width w and height h, then
Volume = length x width x height
l = 10cm, w + h = 18cm
V(h) = 10(18 - h)h = 180h - h^2
V(h) = 180h - h^2
Step-by-step explanation:
Answer:
A. the proper steps that should have been taking would be to first would be to raise 2 to the power of 3, which would give you 8. Then raise it to the power of 1. So the most likely error is C. they added the exponents.
The answer should be 40% because thats the max the density goes
