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3 years ago

Can you please help me?

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

Option (a)

Step-by-step explanation:

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

Slope (m) = $\frac{y_2-y_1}{x_2-x_1}$

Slope of the line passing through (-4, 3) and (6, 3) will be,

m = $\frac{3-3}{6+4}$

m = 0

In other words, slope of any line parallel to x-axis is zero.

Therefore, Option (a) is the answer.

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What expression has the value of 36

harkovskaia [24]

Answer:

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Step-by-step explanation:

i don't know what the question is here

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2 years ago

Are shape I and shape Il similar? If so, give the dilation that proves they are similar. If not, explain why the shapes are not

joja [24]

Answer:

They are similar.

Step-by-step explanation:

They are similar because, the top triangle has one more square to the height as well as the width. If you take one square away from the height and width the top triangle is the same size as the bottom triangle.

7 0

3 years ago

What equation is graphed in this figure? y−4=−13(x+2) y−3=13(x+1) y+2=−3(x−1) y−5=3(x−1) Number graph ranging from negative four

omeli [17]

Answer: The correct option is 3.

Explanation:

It is given that the line passes through (-1,4) and (1,-2).

The slope of the line is,

$m=\frac{y_2-y_1}{x_2-x_1}$

The slope of the given line is,

$m=\frac{-2-4}{1-(-1)} =\frac{-6}{2}=-3$

The point slope form of a line is,

$y-y_1=m(x-x_1)$

Where, m is the slope.

Since slope is -3 and point is (-1,4), then the equation of line is,

$y-4=-3(x+1)$

Since slope is -3 and point is (1,-2), then the equation of line is,

$y+2=-3(x-1)$

Therefore, the correct option is 3.

5 0

3 years ago

Read 2 more answers

The product of 16 and 4 less than a number is 208. Find the number.

svlad2 [7]

This is a word problem signifying an algebraic expression.

Translating this to mathematics:

$16x - 4 = 208$

add 4 to both sides.

$16x = 212$

divide 16 to both sides.

$x = \frac{212}{16}$

this is:

$x = 13.25$

5 0

3 years ago

Problem page an 11 - ft ladder leans against the side of a house. the bottom of the ladder is 8 ft from the side of the house. h

Lisa [10]

A^2 + b^2 = c^2
8^2 + b^2 = 11^2
64 + b^2 = 121
b^2 = 121 - 64
b^2 = 57
b = sqrt 57
b = 7.54 rounds to 7.5 ft <==

5 0

3 years ago

Can you please help me?​

Can you please help me?