Question

When placed near a second charge, a 60-μC charge experiences a force of 0.30 N. What is the electric field strength at the location of the 60-μC charge? What is the strength of the electric field at the location of the test charge?

Answer 1

Answer:

$E=5000N/C$

Step-by-step explanation:

From the question we are told that

Charge $q= 60 \mu C$

Force $F_=0.30N$

Generally the equation for electric field strength is mathematically given as

$E=F/q$

$E=\frac{0.30}{60*10^-^6}$

Therefore

$E=5000N/C$