The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.
<h3>How to solve the length?</h3>
Here, we have two similar right triangles, ΔABE and ΔCDE.
CD = 11 ft
DE = 2 ft
BD = 35 ft
First, find AB:
AB/11 = (35 + 2)/2
AB/11 = 37/2
Cross multiply
AB = (37 × 11)/2
AB = 203.5 ft
Then, apply Pythagorean Theorem to find AE:
AE = √(AB² + BE²)
AE = √(203.5² + 37²)
AE = 207 ft
Therefore, the length of the guy wire is 207 ft.
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Answer:
74º
Step-by-step explanation:
- Ray TV bisects ∠RTS, so ∠RTV=∠STV=(16x-6)º
- We also know that ∠RTS=(26x+18)º
- So, (16x-6)º+(16x-6)º=(26x+18)º
- We don't need parenthesis, 16x-6+16x-6=26x+18
- Combine like terms, 32x-12=26x+18
- Add, 32x=26x+30
- Subtract, 6x=30
- Divide, x=5
- ∠RTV now is [16(5)-6]º=(80-6)º=74º
Answer:
2.55 2.56 2.57
Step-by-step explanation:
Answer:
the middle number
Step-by-step explanation:
