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Luba_88 [7]
2 years ago
5

In how many ways can a committee of 3 men and 2 women be formed from a group of 9 men and 10 ​women?

Mathematics
1 answer:
Setler [38]2 years ago
6 0

Answer:

first you have to find the number of ways 3 men can be chosen, then the number of ways 2 women can be chosen, and then you need to multiply these numbers together to get the number of ways because multiplication will show the total arrangements possibilities. use combination since order does not matter.

number ways for 2 out of 10 women total: 10 choose 2= 45

number of ways for 3 out of 9 men total: 9 choose 3= 84

84x45= 3780

3780 total ways

number of ways

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