Answer:
the 30th term is 239
Step-by-step explanation:
The computation of the 30th term is as follows:
As we know that
a_n = a_1 + (n-1)d
where
a_1 is the first number is the sequence
n = the term
And, d = common difference
Now based on this, the 30th term is
= 152 + (30 - 1) × 3
= 152 + 29 × 3
= 152 + 87
= 239
Hence, the 30th term is 239
Answer:
Step-by-step explanation:
The number of samples is large(greater than or equal to 30). According to the central limit theorem, as the sample size increases, the distribution tends towards normal. The formula is
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = population standard deviation
n = number of samples
From the information given,
µ = 22199
σ = 5300
n = 30
the probability that a senior owes a mean of more than $20,200 is expressed as
P(x > 20200)
Where x is a random variable representing the average credit card debt for college seniors.
For n = 30,
z = (20200 - 22199)/(5300/√30) =
- 2.07
Looking at the normal distribution table, the probability corresponding to the z score is 0.0197
P(x > 20200) = 0.0197
Answer:
answer is false
Step-by-step explanation:
Answer:
There is a horizontal tangent at (0,-4)
The tangent is vertical at (-2,-3) and (2,-3).
Step-by-step explanation:
The given function is defined parametrically by the equations:

and

The tangent function is given by:


The tangent is vertical at when 





When t=1,
and 
When t=-1,
and 
The tangent is vertical at (-2,-3) and (2,-3).
The tangent is horizontal, when
or 


When t=0,
and 
There is a horizontal tangent at (0,-4)
I think it's 6/23 but i might be wrong