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timofeeve [1]
3 years ago
8

The graphed line shown below is y = 5 x minus 10.

Mathematics
1 answer:
harina [27]3 years ago
6 0

Step-by-step explanation:

For 2 lines to form a system with no real solution, the slope of the lines have to be equal and the y-intercept is different.

Hence the answer is y = 5(x + 2).

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What is 47 - -3 ? i haven't found a answer to this - please hurry to answer this , it's a question on my quiz
Paul [167]

Answer:

Here you go, hope this helps

Step-by-step explanation:

50

6 0
2 years ago
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Help please<br><br> my teacher is putting in grade TODAY so i really need help
IRINA_888 [86]

Answer: 130 ft^2

Step-by-step explanation:

Area= 2(wl+hl+hw)

Area= 2(5•10+1•10+1•5)

Area= 2(50+10+5)

Area= 2(65)

Area= 130

5 0
3 years ago
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Select the correct answer.
aleksklad [387]

Answer:

R(2, 4)

Step-by-step explanation:

The general equation for a circle centered at (h,k) with radius, R, is  

(x-h)^2 + (y-k)^2 = R^2

Putting the values in formula,

(x-6)^2 + (y-1)^2 = 5^2

Putting the coordinates (2, 4) of the answer B(2-6)^2 + (4-1)^2 = 25

(-4)^2 + 3^2 = 25

16 + 9 = 25

25 = 25

R.H.S = L.H.S

So according to the above solution,

B) R(2, 4), is the correct answer.

5 0
2 years ago
1.name two acute angles in the figure
kirill115 [55]

Answer:

There isn't a figure. But Acute angles are less than 90 degrees(they're small than an L). Remember it by saying "cute" things are small so acute

Step-by-step explanation:

6 0
3 years ago
Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.
solniwko [45]

For this case we have to:

Letu = x + 1

So:

u ^ 2-4u + 2 = 0

We have the solution will be given by:

u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = 1\\b = -4\\c = 2

Substituting:

u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}

The solutions are:

u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}

Returning the change:

2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}

Answer:

x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}

3 0
2 years ago
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