Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer:
raise a product to a power.
you first simplify the parenthesis in the numerator by raising 2 by the power of three and multiplying the exponents.
i suck at explaining, but after the first step the expression looks like:
Step-by-step explanation:
I think the answer is D because its multiplying by 2 each time
27 inches ......... 3/8
x inches .............8/8
<h3>x = (27×8/8)/(3/8) = 27×8/3 = 216/3 = 72 inches (father)</h3>
Answer:
$30
Step-by-step explanation:
$160-$130=$30
