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Yanka [14]
3 years ago
6

the population P (t) of a culture of bacteria is given by P (t) =-1710t +92,000t+10,000, where t is the time in hours since the

culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.
Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0

The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:

The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.

Answer:

27 hours

Step-by-step explanation:

Equation of population P(t) = –1710t^2+ 92,000t + 10,000

Find the derivative of the function to find the critical value

dP/dt = -2(1710)t + 92000

         = -3420t + 92000

Find the critical value by equating dP/dt = 0

-3420t + 92000 = 0

92000 = 3420t

t = 92000/3420 = 26.90

Check if it really have max value through 2nd derivative

d(dP)/dt^2 = -3420

2nd derivative is negative, hence it has maximum value

So, the time when it is maximum is 26.9 or 27 hours

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statuscvo [17]

Answer:

11 & 5 are the factors of 55

Step-by-step explanation:

Factors of 55

11 × 5 = 55

Thus, 11 & 5 are the factors of 55

 

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7 0
3 years ago
Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and
Citrus2011 [14]

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

5 0
3 years ago
a new car, originally worth $35,795, depreciates at a rate of 17% per year. The value of the car can be represented by the equat
Sergio [31]

We have been given that a new car, originally worth $35,795, depreciates at a rate of 17% per year. The value of the car can be represented by the equation y=35795(0.83)^x, where x represents the number of years since purchase and y represents the value (in dollars) of the car.

To find the value of car of after 5 years, we will substitute x=5 in our given equation as:

y=35795(0.83)^5

y=35795\cdot (0.3939040643)

y=14099.79598

Upon rounding to nearest tenth, we will get:

y\approx 14099.8

Therefore, the car will be worth $14,099.8 after 5 years it is first purchased.

Since $14,099.8 is less than original value of car, therefore, we know hat value of car is depreciating and $14,099.8 is correct answer.

We also know that an exponential decay function is in form y=a(1-r)^x, where,

y = Final value after t years,

a = Initial value,

r = Decay rate in decimal form,

x= Time.

17\%=\frac{17}{100}=0.17

y=35795(1-0.17)^x

y=35795(0.83)^x

8 0
3 years ago
HELPPP WILL MARK YOU BRAINLIEST
Tems11 [23]

Answer:

BC = 30

Step-by-step explanation:

AC = 48, AC = AB + BC, AB = 2x + 2 , BC = 3x + 6 => AC = 2x + 2 + 3x + 6  =>

=> AC = 5x + 8 , AC = 48 => 5x = 40 => x = 8 , BC = 3x + 6 => BC = 24 + 6 = 30

3 0
3 years ago
If you wrote all of the numbers from 300 to 400 on a piece of paper, how many times would you have written the number 3
Zanzabum
Hello :)

You have writen 111 times :) . 
8 0
3 years ago
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