<h2><em>Answer:</em></h2><h2><em>=</em><em>12</em></h2><h2><em>12step</em><em> </em><em>by step explanation:</em></h2><h2><em>=</em><em>solution:</em></h2><h2><em>solution: area of gym= 144</em></h2><h2><em>solution: area of gym= 144we know that,</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L²</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L²</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144)</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144) or, 12= L </em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144) or, 12= L therefore, L = 12 </em></h2>
Answer:
4+b
Step-by-step explanation:
Answer: B is 0 A is 1 D 2 E 3
Step-by-step explanation:
Answer:
a) 4.387
b) Yes, because np & npq are greater than 10.
c) = 0.017
Step-by-step explanation:
Give data:
p = 0.69
n = 90
a) a
E(X) = np = 62.1


= 4.387
b)
np = 62.1
q = 1 - p = 1 - 0.69 = 0.31
npq = 19.251
Yes, because np & npq are greater than 10.
c.
[continuity correction]

= P(Z> 2.14 )
= 1 - P(Z<2.14)
= 1 - 0.983 (using table)
= 0.017
Check the picture below
so.. hmm notice the center h,k and the major and minor axis components, thus just plug them in.