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dmitriy555 [2]
3 years ago
10

HOW CAN YOU DETERMINE THE END BEHAVIOR OF A POLYNOMIAL FUNCTION?

Mathematics
2 answers:
fiasKO [112]3 years ago
4 0

Answer:

as x approaches positive infinity or negative infinity, the degree and the leading coefficient of a polynomial function determines the end behavior of the graph

straight from gogle

Svetlanka [38]3 years ago
3 0

Answer:

Hi there!

The end behavior of a function f describes the behavior of the graph of the function at the "ends" of the x-axis. In other words, the end behavior of a function describes the trend of the graph if we look to the right end of the x-axis (as x approaches +∞ ) and to the left end of the x-axis

I'm sorry if that is not clear enough!

Best wishes,

         Pandora

Step-by-step explanation:

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Which graph does NOT represent a function?<br> A)<br> A<br> B)<br> B<br> C)<br> С<br> D)<br> D
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Answer:

(B)

Step-by-step explanation:

it is an undefined

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758 - 387 = ___ - 200l
Iteru [2.4K]

Step-by-step explanation:

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3 years ago
Read 2 more answers
What is the distance points for (2,-2) and (0,-9)
Ksivusya [100]

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

Step-by-step explanation:

The given is,

         Two points are (2,-2) and (0,-9)

Step:1

         By graphical method,

         For two points (2,-2) and  (0,-9)

                  First point (2,-2)

                             The values of x=2 and y=-9 noted in the graph

                  Second point (0,-9)

                              The values of x=0 and y=-9 noted in the graph

                  Now join the two points, measure the distance between the two points,

                   Distance between points are 7.3 units.

                                          ( OR )

Step:1

        By formula method,

              Distance =   \sqrt{(x_{2}- x_{2})  ^{2}+ (y_{2}-y_{1})  ^{2}  }

       Where,

               ( 2,-2) are (x_{1},y_{1})

               (0,-9) are (x_{2},y_{2})

       From the values,

                             = \sqrt{(0- 2)  ^{2}+ (-9+2)  ^{2}  }

                            =  \sqrt{(- 2)  ^{2}+ (-7)  ^{2}  }

                            = \sqrt{4+49  }

                            = \sqrt{53}

                            = 7.280

                            ≅ 7.3

            Distance = 7.3

Result:

           The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

5 0
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prisoha [69]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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