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Alex777 [14]
3 years ago
10

Find a​ point-slope form for the line with slope

Mathematics
1 answer:
Katen [24]3 years ago
7 0

Answer:

It is Third quardant in Graph

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Write the equation of the line given the slope and a point through the line passes
Anuta_ua [19.1K]

Answer:

1.) Y = 5/3 X + 4

2.) Y = 9/4 X - 27/4

Step-by-step explanation:

Given the slope and the coordinate, linear equation of a line can be expressed by using general linear equation. Which is

Y = MX + C

Where the

Slope M = 5/3

Coordinate = (-3,-1) in which

X = -3, Y = -1

Substitute X, Y and M into the general linear equation to achieve C

-1 = 5/3(-3) + C

-1 = - 5 + C

C = 5 - 1

C = 4

Substitute C and M back into the general linear equation.

Therefore, the equation of the line given the slope and a point through the line passes 5/3, and (-3,-1) to be

Y = 5/3 X + 4

2.) Also,

Slope M = 9/4

Coordinate = (3,0) where X = 3, Y = 0

Substitute X, Y and M into the general linear equation to obtain C

0 = 9/4 (3) + C

C = - 27/4

Substitutes C and M back into the general linear equation

Therefore, the equation of the line given the slope and a point through the line passes 9/4 and (3,0)

Y = 9/4 X - 27/4

4 0
3 years ago
Please help me I need it tomorrow at least until 7:50 or8:30
Lemur [1.5K]
3 pints, 1gallon, 1quart
7 0
3 years ago
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What's 5.78,-5 7/8,-5.9 from least to greatest?
blagie [28]
-5.9, -5 7/8, 5.78 because negative is less than zero and 7/8= .850 :)
3 0
3 years ago
If you want to be friends add my sc
Alex777 [14]

Answer:

I dont have sc

Step-by-step explanation:

7 0
3 years ago
You have 200 dice in a bag. One of the dice has a six on all sides so it will land on a six every time you roll it. The other 19
LiRa [457]

Answer:

Step-by-step explanation:

There are 200 dice out of which 199 are fair

Prob for 6 in one special die = 1 and

Prob for 6 in other die = 1/6

A1- drawing special die and A2 = drawing any other die

A1 and A2 are mutually exclusive and exhaustive

P(A1) = 1/200 and P(A2) = 199/200

B = getting 6

i) Required probability

= P(A1/B) = \frac{P(A1B)}{P(A1B)+P(A2B)} \\

P(A1B) = \frac{1}{200} *1 = \frac{1}{200}

P(A2B) = \frac{199}{200}*\frac{1}{6}=\frac{199}{1200}

P(B) = \frac{205}{1200} =\frac{41}{240}

P(A1/B) = \frac{1/200}{41/240} =\frac{7}{205}

P(A2/B) = \frac{199/1200}{41/240} =\frac{199}{205}

4 0
3 years ago
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