<span>100 = 0.046s^2 - 0.199s + 0.264
0 = 0.046s^2 - 0.199s - 99.736
s= 48.77691127... or -44.45082431 (reject)
The car's speed was approximately 48.8 mph.</span>
With this information we can set up 2 equations:
x + y = 312 (# of tickets sold for adults + # of tickets sold to adults = 312)
12x + 5y = 2204 ( # of tickets sold for adults times $12 + # of tickets sold to adults times $5 = $2204)
Where x is how many tickets were sold to adults and y how many tickets were sold to children
Now we can solve this system of equations by substitution:
isolate y in the first equation to find its value and plug it in the second equation
x + y = 312
isolate y by subtracting x from both sides:
x - x + y = 312
y = 312 - x
Apply y = 312 - x to the second equation
12x + 5y = 2204
12x + 5( 312 - x) = 2204
12x + 1560 - 5x = 2204
7x + 1560 = 2204
Subtract 1560 from both sides to isolate x
7x + 1560 - 1560 = 2204 - 1560
7x = 644
Divide both sides by 7
7/7x = 644/7
x = 92
Now plugin 92 for x in the first equation to find the value of y
x + y = 312
92 + y = 312
subtract 92 from both sides
92 - 92 + y = 312 - 92
y = 220
x = 92, y = 220
92 tickets were sold to adults and 220 tickets were sold to children
Hope it helps :)
Branliest would be appreciated
5x2-3x=25
Divide each term by 5:
x^2 - 3/5x = 5
Make a trinomial square of the left side by taking the square of half of the coefficient of x.
The coefficient of x is -3, so the square would be (-3/10)^2
Add that to both sides of the equation.
Now you have:
x^2 - 3/5x + (-3/10)^2 = 5 + (-3/10)^2
Simplify both sides:
x^2 -3/5x +9/100 = 509/100
Factor the trinomial:
(x-3/10)^2 = 509/100
Solve for x, , take the square root of both sides:
x-3/10 = +/-√509 / 100
Simplify the right side:
x-3/10 = +/-√509/10
Add 3/10 to both sides:
X = +/-√509/10 + 3/10 ( this is the exact form)
You can then find the decimal answer if needed.
9514 1404 393
Answer:
D
Step-by-step explanation:
If the actual value is above the value estimated from the tangent to the curve, then the curve must have a positive second derivative: it curves upward.
Only curve D in the second attachment has upward curvature.
