158 natural numbers from 78 to 234, and 699 whole numbers from 24 to 721. Step-by-step explanation: Natural numbers are positive integers (whole numbers), so all numbers from the range of 78 to 234 would be included, including 78 and 234 itself.

Hope this helps, have a wonderful day/night, stay safe, happy holidays, and merry christmas!

6 0

2 years ago

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Translate radical expressions into expressions with rational exponents, and vice versa. Simplify numerical

dmitriy555 [2]

Answer:

a) ( $\sqrt[n]{x}$ ) the n will be 5 the x will be (-32/243)^2.

b) written the same as a. except the c will replace the n and x will be (2y)^b.

c) the answer will be 0.4^3.

d) the answer would be (st)^v/u.

Hope this helps!

Brainliest?

3 0

2 years ago

the figure below has an volume of 108^3 in and a height of 9 in. what are the possible dimensions of the base?

Alenkinab [10]

Area of base

Volume/Height
108/9
12in²

So possible dimensions are optionB given

1/2BH
1/2(4)(6(
2(6)
12in²

Verified

7 0

1 year ago

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The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.

slamgirl [31]

Answer:

$b=-6\\c=7$

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

$y=a(x-x_1)(x-x_2)$

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

$a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}$

substitute

$y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))$

Applying the distributive property convert to expanded form

$y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})$

$y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)$

$y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7$

$y=x^2-6x+7$

therefore

$b=-6\\c=7$

7 0

2 years ago