So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 55$ obviously. Secondly 45$ for the next 10 boxes.
So for now we can simply calculate that we have spent around 100$ which means 20 boxes. The remaining money left is 77$ so we can buy 77/3.5 = 22 only 22 boxes with that money. Hence a total of 42 boxes.
Answer: (b) A
<u>Step-by-step explanation:</u>
A: the center of the circle
B: the diameter of the circle
C: the radius of the circle
D: <em>not sure, could be the perimeter</em>
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Circles are named by their center, so this is named "Circle A".
Answer:
A landscape architect recommends installing a triangular statue with
vertices at (10, −10), (10, −8), and (7, −10).
a. Is the triangle congruent to triangle T ? Justify your answer.
b. Propose a series of rigid motions that justifies your answer to part a.
6. Another landscape architect recommends installing a triangular statue
Step-by-step explanation:A landscape architect recommends installing a triangular statue with
vertices at (10, −10), (10, −8), and (7, −10).
a. Is the triangle congruent to triangle T ? Justify your answer.
b. Propose a series of rigid motions that justifies your answer to part a.
6. Another landscape architect recommends installing a triangular statue
Answer:
a. 90 pack
b. $0.27
c. $0.18
d. $0.21
e. 60 pack
Step-by-step explanation:
a. i think the 90 pack container should be having least unit rate per pack,as purchasing in bulk amount the cost of a unit should be reduced to some amount which is must to lure the customer to purchase in bulk amounts.
b. unit price = total cost of container ÷ number of individual units inside it
for 20 pack, unit rate = 5.49÷20 = $0.27
c. for 60 pack, unit rate = 10.97÷60 =$0.18
d. for 90 pack, unit rate = 18.95÷90 =$0.21
e. ∴ the 60 pack container has the least unit rate per pack which is in contrary with our expectation of 90 pack to be lowest expecting bulk order.
<h3>
Answer: log(2)</h3>
Explanation:
The rule to use here is log(x)-log(y) = log(x/y)
So,
log(6)-log(3) = log(6/3) = log(2)
