I think the answer is b. cos(pi theta)= -0.6
Answer:
0.1569 = 15.69%
Step-by-step explanation:
If eight calls were placed, and we need to know the probability of exactly two calls were occupied, we need to calculate a combination of 8 choose 2 (all the combinations of 2 occupied calls in the 8 total calls), and multiply by the probability of each case in the 8 calls (2 cases occupied and 6 cases not occupied):
P(8,2) = C(8,2) * p(occupied)^2 * p(not_occupied)^6
P(8,2) = (8*7/2) * (0.45)^2 * (0.55)^6
P(8,2) = 28 * 0.2025 * 0.02768 = 0.1569 = 15.69%
8% I am sorry if I am wrong
Answer:
x-int (6.2, 0)
y-int (0, 3.1)
Step-by-step explanation:
x-intercept is found when y = 0.
y-intercept is found when x = 0.
Step 1: Define equation
2x + 4y = 12.4
Step 2: Find x-intercept
<em>Substitute y for 0.</em>
2x + 4(0) = 12.4
2x = 12.4
x = 6.2
(6.2, 0)
Step 3: Find y-intercept
<em>Substitute x for 0.</em>
2(0) + 4y = 12.4
4y = 12.4
y = 3.1
(0, 3.1)