A 90 degree clockwise rotation about origin followed by a transition 2 units to the right
We would need to look over the z table to find the area under the standard normal distribution curve to the left of z = 1.04. Then we'll subtract it from 1 to get the proportion of a normal distribution corresponding to z scores greater than 1.04.
By looking at the z table, we can see that the area to the left of z = 1.04 is 0.8508. So the proportion of a normal distribution to the right of z = 1.04 is 1 – 0.8508 = 0.1492.
The answer is 0.1492.
Answer:
1.008
1.08
1.6
1.6071
Step-by-step explanation:
least to greatist
Answer:
1/2
hope this helps
have a good day :)
Step-by-step explanation:
Everywhere you see z, replace the letter with 18.
z/[(3- 2z)] + 4(z - 8)
18/[(3 - 2(18))] + 4(18 - 8)
You finish.