2 years ago

Y=x^2, y=x+12 solve by substitution method

Mathematics

1 answer:

Goshia [24]2 years ago

5 0

Answer:

y=x^2

y=x+12

x^2=x+12

x=-3

x=4

y=-3+12

y=4+12

y=9

y=16

(x1,y1)=(-3,9)

(x2,y2)=(4,16)

Step-by-step explanation:

Hope this helps!

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Hello!!

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2 years ago

1. What value of x makes the equation 6x - 14+ 3(2x - 1) = 5 - 2(x - 10) true?

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yeet this is a thicc problem...

6x - 14 + 3(2x-1) = 5 - 2(x-10)

first expand

6x - 14 + 6x -3 = 5 -2x-20

now put constants and variables on either sides of the thingamajig

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