All categories

3 years ago

Which of these steps will eliminate a variable in this system?

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

3 0

C. multiply the second equation by two. Then add the equations

You might be interested in

Manolo and Annalisa make handbags. Manolo made 16 handbags the first day and 12 each day after that. Annalisa made 8 the first d

vivado [14]

Answer:

b and c

that is is it

7 0

2 years ago

Read 2 more answers

Please answer this for me.

Nastasia [14]

Answer:

(x + 5)**2 + (y + 2)**2 = 25

Step-by-step explanation:

We know that the general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius. The graph shows the center at (-5, -2), and the radius of 5. So plugging this in

(x - -5)**2 + (y - - 2)**2 = 5**2

(x + 5)**2 + (y + 2)**2 = 25

6 0

2 years ago

What are the factors of 3x^2 + 23x − 8?

Margaret [11]

<span>3x</span>²<span> + 23x − 8 = 3x</span>² + 24x - x - 8 = 3x(x+8) - (x+8) = (x+8)(3x-1)

8 0

3 years ago

!!! PLEASE HELP ME !!!

andrew11 [14]

Answer:

Be an GH

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

3 0

3 years ago