Which of these steps will eliminate a variable in this system?

Find the values of m and n Need help, thank you!!!

Wewaii [24]

Answer:

m=45 degrees

n=15 degrees

Step-by-step explanation:

m=45 degrees because other 2 angles in it's triangle =90+45=135 degrees

180 degrees in any triangle so m=180-135=45 degrees.

m+n=60 degrees so n=60-45=15 degrees

6 0

3 years ago

A line passes through the points (-3, -7) and (7, -6). What is its equation in point-slope form?

HACTEHA [7]

Answer:

1/10

Step-by-step explanation:

not sure

3 0

3 years ago

If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact.

brilliants [131]

Degree: 5; leading coefficient: 10

Option D is correct.

Step-by-step explanation:

We need to identify if $f(x) = 10x^5 + 7x^4+5$ is a polynomial function, then state its degree and leading coefficient or not.

Polynomial

A polynomial is an algebraic expression containing two or more terms that have same variables but may have different exponents combined through mathematical symbol(+,-,*or/)

So, $f(x) = 10x^5 + 7x^4+5$ is a polynomial function

Degree of polynomial

The degree of polynomial is the highest degree obtained by sum of all exponents of individual terms in the polynomial.

So, $f(x) = 10x^5 + 7x^4+5$ has highest degree 5

Degree = 5

Leading Coefficient

The leading coefficient is the coefficient of first term of the polynomial.

So, $f(x) = 10x^5 + 7x^4+5$ has leading coefficient = 10

So, Leading coefficient = 10

So, Degree: 5; leading coefficient: 10

Option D is correct.

Keywords: Polynomials

Learn more about Polynomials at:

#learnwithBrainly

3 0

3 years ago

The Institute of Management Accountants (IMA) conducted a survey of senior finance professionals to gauge members’ thoughts on g

DochEvi [55]

Answer:

(1) The probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69% is 0.3674.

(2) The two population percentages that will contain the sample percentage with probability 90% are 0.57 and 0.73.

(3) The two population percentages that will contain the sample percentage with probability 95% are 0.55 and 0.75.

Step-by-step explanation:

Let X = number of senior professionals who thought that global warming is having a significant impact on the environment.

The random variable X follows a Binomial distribution with parameters n = 100 and p = 0.65.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of p if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

Check the conditions as follows:

$np= 100\times 0.65=65>10\\n(1-p)=100\times (1-0.65)=35>10$

Thus, a Normal approximation to binomial can be applied.

So, $\hat p\sim N(p, \frac{p(1-p)}{n})=N(0.65, 0.002275)$ .

(1)

Compute the value of $P(0.64$ as follows:

$P(0.64$

$=P(-0.20$

Thus, the probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69% is 0.3674.

(2)

Let $p_{1}$ and $p_{2}$ be the two population percentages that will contain the sample percentage with probability 90%.

That is,

$P(p_{1}$

Then,

$P(p_{1}$

$P(\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$P(-z$

The value of z for P (Z < z) = 0.95 is

z = 1.65.

Compute the value of $p_{1}$ and $p_{2}$ as follows:

$-z=\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}\\-1.65=\frac{p_{1}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{1}=0.65-(1.65\times 0.05)\\p_{1}=0.5675\\p_{1}\approx0.57$ $z=\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}}\\1.65=\frac{p_{2}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{2}=0.65+(1.65\times 0.05)\\p_{1}=0.7325\\p_{1}\approx0.73$

Thus, the two population percentages that will contain the sample percentage with probability 90% are 0.57 and 0.73.

(3)

Let $p_{1}$ and $p_{2}$ be the two population percentages that will contain the sample percentage with probability 95%.

That is,

$P(p_{1}$

Then,

$P(p_{1}$

$P(\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}$

$P(-z$

The value of z for P (Z < z) = 0.975 is

z = 1.96.

Compute the value of $p_{1}$ and $p_{2}$ as follows:

$-z=\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}\\-1.96=\frac{p_{1}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{1}=0.65-(1.96\times 0.05)\\p_{1}=0.552\\p_{1}\approx0.55$ $z=\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}}\\1.96=\frac{p_{2}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{2}=0.65+(1.96\times 0.05)\\p_{1}=0.748\\p_{1}\approx0.75$

Thus, the two population percentages that will contain the sample percentage with probability 95% are 0.55 and 0.75.

7 0

4 years ago

An interior angle of a regular polygon has a measure of 108°. what type of polygon is it? pentagon hexagon octagon nonagon

melamori03 [73]

$Exterior \ = \ supplement
\\ 180-108 = 72
\\ 360/72 = 5
\\ Polygon \ is \ a \ pentagon.$

7 0

4 years ago

Read 2 more answers