The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.
Step-by-step explanation:
y = 9x - 7
When x = 8
y = 9.8 - 7
y = 72 - 7
y = 65
When x = 6
y = 9.6 - 7
y = 54 - 7
y = 47
When x = 7
y = 9.7 - 7
y = 63 - 7
y = 56
When x = -8
y = 9.(-8) - 7
y = -72 - 7
y = -79
When x = 4
y = 9.4 - 7
y = 36 - 7
y = 29
.4 is smallest, 1/2 , then 60% is greatest.
Answer:
d=20
Step-by-step explanation:
To find the distance between 2 points we use the distance formula
d = √(x2 - x1)²+(y2 - y1)²
The given points are (x1= -8, y1 = -6) and (x2 = 4, y2 = 10).
Substitute the given points into the distance formula.
d = √(4 + 8)²+(10 +6)²
d = √144+252
d= √400
d = 20
Answer:
9
Step-by-step explanation:
