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2 years ago

Help I will give brainlest!

Mathematics

1 answer:

elena55 [62]2 years ago

7 0

Answer:

it A={days of the week } find N(A) list the following

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Graph the linear equation. Find three

Sever21 [200]

Y=1/3x+2
(-6,0)
(0,2)
(6,4)

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3 years ago

Karen finished watching a movie at 1:00 PM. The movie lasted 1 hour 38 minutes. at what time Karen started watching the movie. -

Andrew [12]

The correct answer would be 11:32am. i hope this helps!

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3 years ago

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What is 5 3/8- 2 7/8

ella [17]

Answer:

2 1/4

Step-by-step explanation:

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3 years ago

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I NEED HELP PLEASE, THANKS! :)

NISA [10]

Answer: $\bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}$

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

$\sec x=\dfrac{1}{\cos}$

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0 sec x - 1 = 0

sec x = -2 sec x = 1

$\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0$

8 0

3 years ago

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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

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3 years ago