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muminat
2 years ago
7

The locally linear approximation of the differentiable function f at x=2 is used to approximate the value of f(2.3). The approxi

mation at x=2.3 is an underestimate of the corresponding function value at x=2.3. Which of the following could be the graph of f?
Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
8 0

9514 1404 393

Answer:

  D

Step-by-step explanation:

If the actual value is above the value estimated from the tangent to the curve, then the curve must have a positive second derivative: it curves upward.

Only curve D in the second attachment has upward curvature.

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Sabina bought a samsung mobile set for rs.15750 after getting the discount of 10%. Find the price of mobile set before discount.
Elanso [62]

Answer:

Step-by-step explanation:

90/100 * x = 15750

0.9 x = 15750

x = 15750/0.9

x = 17500

Now check this by taking 10% off. Do you get 15750?

Let's see

10/100 of 17500 = 1750

Subtract that from 17500

17500 - 1750 = 15750 which is exactly what you should get.

7 0
2 years ago
Find the average rate of change of g(x) = 1x3 + 2 from x =<br> 1 to x = 4
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Explanation:

The

average rate of change

of g(x) over an interval between 2 points (a ,g(a)) and (b ,g(b) is the slope of the

secant line

connecting the 2 points.

To calculate the average rate of change between the 2 points use.

∣

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

g

(

b

)

−

g

(

a

)

b

−

a

a

a

∣

∣

∣

−−−−−−−−−−−−−−−

g

(

6

)

=

6

2

−

6

+

3

=

33

and

g

(

4

)

=

4

2

−

4

+

3

=

15

Thus the average rate of change between (4 ,15) and (6 ,33) is

33

−

15

6

−

4

=

18

2

=

9

This means that the average of all the slopes of lines tangent to the graph of g(x) between (4 ,15) and (6 ,33) is 9

3 0
2 years ago
A right cone has a surface area of 440 square inches and a radius of 7 inches. Find its slant height.
EastWind [94]

Answer:

Surface Area of right cone  

               =\pi r(r+\sqrt{h^2 + r^2}

440 = \pi *7*(7+\sqrt{h^2+7^2})\\\\440 = 7\pi (7 + \sqrt{h^2+7^2})\\\\\frac{440}{7\pi } = 7 + \sqrt{h^2+49}\\\\\frac{440}{7\pi } - 7 = \sqrt{h^2+49}\\\\\frac{440-49\pi}{7\pi} =\sqrt{h^2+49}\\\\

\frac{286.062}{21.99} =\sqrt{h^2+49}\\\\13.0087= \sqrt{h^2+49}\\\\(13.0087)^2 = (\sqrt{h^2+49})^2\\\\169.227 = h^2 +49\\\\169.227 - 49 =h^2\\\\120.227 = h^2\\\\h = \sqrt{120.227}  = 10.96in

7 0
2 years ago
Help me ASAP for this question
ludmilkaskok [199]

Answer:

Your answer is 7

Hope this helps!

Step-by-step explanation:

You plug 14 in for x then just do 14-7 and you will get 7

7 0
2 years ago
Read 2 more answers
BRAINLIESSTTTT!!!!
andrew11 [14]

7.211; Starting from the left to right, x1=3 x2=7, y1=2 y2=8. Plug these in to the distance formula \sqrt{(x2-x1)^2+(y2-y1)^2

(7-3)^2+(8-2)^2

(4)^2+(6)^2

16+36

sqrt 52

7.211

7 0
2 years ago
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