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3 years ago

F(x) = -1/2x^2 + 3/2x - 2 I need to find the zeros

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

4 0

Answer:

{-1, 4}

Step-by-step explanation:

In the given f(x) = -1/2x^2 + 3/2x - 2

set f(x) = 0 and then multiply all the numeric terms by -2 to remove the fractions:

f(x) = -1/2x^2 + 3/2x - 2 = 0 => 1x^2 - 3x - 4 = 0

This factors into (x - 4)(x + 1) = 0, whose roots are {-1, 4}. These are the zeros.

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If a= 2,b= -1,c= -3 and d = -2 evaluate the following Q1. ab-3b+4d , Q2. 5abd+3bc-2ax and Q3. 2(ab)^2+bc^2

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3 years ago

What is the factor tree of 99 and 165 and what is the GCF?

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3 years ago

Solve c: P = a+b+c+d / 4

m_a_m_a [10]

Answer:

as written: c = P - a - b - d/4
with parentheses: c = 4P - a - b - d

Step-by-step explanation:

The meaning of the given expression is ...

P = a + b + c + (d/4)

To solve for c, subtract all the terms on the right side not containing c.

P -(a + b + (d/4)) = c

c = P - a - b - (d/4)

_____

In such equations, parentheses are commonly missing. If that is the case here, then first we undo the division by 4, then we subtract the "not c" terms.

P = (a + b + c + d)/4 . . . . maybe what you meant

4P = a + b + c + d . . . . . . multiply by 4

4P - (a +b +d) = c

c = 4P -a -b -d

8 0

3 years ago

Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?

BlackZzzverrR [31]

Answer:

$\boxed{\sf a = 9 }$

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

$\sf\longrightarrow 3x - 2y +7=0$

$\sf\longrightarrow 6x +ay -18 = 0$

Step 1 : Convert the equations in slope intercept form of the line .

$\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}$

and ,

$\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}$

Step 2: Find the slope of the lines :-

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

$\sf\longrightarrow Slope_1 = \dfrac{3}{2}$