Question

F(x) = -1/2x^2 + 3/2x - 2 I need to find the zeros​

Answer 1

Answer:

{-1, 4}

Step-by-step explanation:

In the given f(x) = -1/2x^2 + 3/2x - 2

set f(x) = 0 and then multiply all the numeric terms by -2 to remove the fractions:

f(x) = -1/2x^2 + 3/2x - 2 = 0  =>  1x^2 - 3x - 4 = 0  

This factors into (x - 4)(x + 1) = 0, whose roots are {-1, 4}.  These are the zeros.