F(x) = -1/2x^2 + 3/2x - 2 I need to find the zeros

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

4 0

Answer:

{-1, 4}

Step-by-step explanation:

In the given f(x) = -1/2x^2 + 3/2x - 2

set f(x) = 0 and then multiply all the numeric terms by -2 to remove the fractions:

f(x) = -1/2x^2 + 3/2x - 2 = 0 => 1x^2 - 3x - 4 = 0

This factors into (x - 4)(x + 1) = 0, whose roots are {-1, 4}. These are the zeros.

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