Step-by-step explanation:
You must exclude any intersecting faces (faces that are shared), because these faces are not on the surface.
For example, an ice cream cone can be approximated as a composite figure of a hemisphere on top of a cone. The circular base of the hemisphere and the circular base of the cone are intersecting, so you must exclude it when finding the surface area.
From the fact that the shape is a square, we know that one of the angles of the triangle in question must by 90 degrees (the lower left angle in this case).
The triangle formed is also an isosceles triangle and therefore the two smaller angles must be equal to each other. (upper left and lower right)
On top of this, we also know that the total of the angles must be 180 due to the fact that all triangles have interior angles that add to 180.
90 + (lower right) + (upper left) = 180
Since lower right and upper left are equal, we can use a single variable to represent them both.
90 + a + a = 180
90 + 2a = 180
2a = 90
a = 45
So, the degree of the lower right angle is 45. We can take this value and set 4x + 17 equal to it.
4x + 17 = 45
4x = 28
x = 7
Therefore, x is equal to 7.
11 2/3, I think. 2*3 + 1 = 7 & 7/3*5/1 (where you do straight multiplication) you get 35/3 which simplifies to 11 2/3. Hope this helped, but um what is the weight measurement or is that not mentioned?
B ) 75 Miles per hour
75 + 64(10) = 640 + 75 = 715
715 ÷ 11 ( how many drivers ) = 65
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
