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3 years ago

What is the quadruple of 2-2

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

3 0

Answer:

Please check the explanation below.

Step-by-step explanation:

As we know that quadruple is basically a fourfold amount or number.

For example,

The quadruple of 6 is 24.

4 x 6 = 24

Similarly, the quadruple of 10 is 40.

4 x 10 = 40

Now, let me solve your query.

Given the expression

2 - 2

2-2 = 0

we have to determine the quadruple of 0.

i.e.

4 x 0 = 0

Therefore, 0 is the quadruple of 2-2 (or 0).

I hope, it has cleared your concept.

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I need to know what the equation is for this graph..

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Answer:

The choice second

$y = \frac{1}{3} \times ( \frac{1}{4} ) ^{x}$

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2 years ago

What is the constant term in the expression 5x^2+7x+4?

Doss [256]

Answer: 4

Step-by-step explanation:

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3 years ago

Read 2 more answers

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago

Given that a = 10,

tankabanditka [31]

Since $a = 10$ and $b = 2x + 5$ , we have

$ab=10(2x+5)=20x+50$

So, the equation becomes

$ab = 6x^2 +11x-10 \iff 20x+50= 6x^2 +11x-10 \iff 6x^2-9x-60=0$

The solutions to this equation are 4 and -5/2, so I'm afraid there's a typo in your question.

3 0

3 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

MAVERICK [17]

Answer:

(-2,-5)

Step-by-step explanation:

y = 2x-1

3x-y = -1

We can use substitution

3x - (2x-1) = -1

Distribute the minus sign

3x -2x+1 = -1

x +1 =-1

Subtract 1 from each side

x+1-1 = -1-1

x=-2

Now we need to find y

y = 2x-1

y = 2(-2) -1

y = -4-1

y = -5

(-2,-5)

3 0

3 years ago