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Tamiku [17]
3 years ago
14

State True or False: 1. Application software can run without the presence of system software. 2. . A language processor translat

es the machine language into programming language. Backup is a process of shrinking the files on a disk. VisiCalc was the first computer spreadsheet program. An interpreter translates the whole program into an equivalent code in one go.​
Computers and Technology
1 answer:
joja [24]3 years ago
3 0

Answer:

2. translates program written in any programming language into Machine language

last ko . false

Explanation:

aru aaunna

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Attackers need a certain amount of information before launching their attack. One common place to find information is to go thro
VARVARA [1.3K]

Answer:

The answer is Letter D. Dumpster diving.

Explanation:

This process of going through a target's trash is known in the community as dumpster diving. This attack is a technique used to retrieve information that could be used to carry out an attack on a computer network.

It is important to inform that the dumpster diving it is not limited to searching through  the trash for obvious treasures like acess codes or passwords written down on sticky notes.

8 0
2 years ago
Assuming that the actual process ids of the parent and child process are 2600 and 2650 respectively, what will be printed out at
VashaNatasha [74]

Answer:

Output explanation to the given code can be defined as follows:

Explanation:

In A the output is 0 , It will return fork value of the child process that is 0. so, 0 is printed during child process.  

In B the output is 2650 , in which the getpid() method returns the child process id  value that is 2650.  

In C the output is 140, As it is declared in key, all process have their own "value" copies. 20 are inserted during childhood, so 140 are written.  

In D the output is 2650, its fork() method returns the child ID to the parent process. so the value 2650 is printed.  

In E the output is 2600, Its getpid() method will returns parent process id  that is equal to 2600.  

In F the output is 120 Since the value is declared in primary, all process so their own "value" copies. 120 will be printed during process.

4 0
3 years ago
Which task can be completed with the Template Organizer?
spin [16.1K]

Answer:

B is the answer

Explanation:

i just got it right

8 0
2 years ago
Read 2 more answers
5 características de la obsolescencia programada...
snow_lady [41]

Answer:

Obsolescencia programada es cuando un producto está diseñado deliberadamente para tener un tiempo de vida específico. ... Los productos dejan de funcionar al cabo de un tiempo, no porque estén estropeados, sino por que han sido diseñados para fallar al cabo de ese periodo.

Explanation:

espero y esto te pueda ayudar

4 0
3 years ago
Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F
yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.  

No understudy who got a confinement got an A.  

No understudy who got a confinement is on the respect roll.  

No understudy who got an A missed class.  

No understudy who got a confinement got an A.  

No understudy who got a confinement missed class  

Explanation:

M(x): x missed class  

An (x): x got an A.  

D(x): x got a confinement.  

¬∃x (A(x) ∧ M(x))  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ M(x))  

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope got a confinement.  

Penelope missed class.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a confinement.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope didn't miss class.  

Penelope didn't get imprisonment.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got imprisonment.  

Each understudy who missed class or got imprisonment didn't get an A.  

Penelope is an understudy in the class.  

Penelope got an A.  

Penelope didn't get repression.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a repression.  

An (ax): x got an A.  

H(x): x is on the regard roll  

An (x): x got an A.  

D(x): x got a repression.  

∀x (H(x) → A(x)) a  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ H(x))  

Real.  

1. ∀x (H(x) → A(x)) Hypothesis  

2. c is a self-self-assured element Element definition  

3. H(c) → A(c) Universal dispatch, 1, 2  

4. ¬∃x (D(x) ∧ A(x)) Hypothesis  

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4  

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5  

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6  

8. ¬A(c) ∨ ¬D(c) Commutative law, 7  

9. ¬H(c) ∨ A(c) Conditional character, 3  

10. A(c) ∨ ¬H(c) Commutative law, 9  

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10  

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11  

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12  

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13  

4 0
3 years ago
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