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stepladder [879]
3 years ago
12

1+2+3+4+5+.........+100= ? The sum of 100 consecutive interger from 1 to 100

Mathematics
2 answers:
Mama L [17]3 years ago
6 0

Answer:

5050

Step-by-step explanation:

Ace here!

So, you could go through and add up everything but that takes a while, and there's a much easier way to do this. Let's write a rough sample of the numbers.

1, 2, 3, 4, 5....96, 97, 98, 99, 100.

Now, let's look at these numbers. Notice how if we add the two numbers on the leftmost and the rightmost, we get 101 (1+100). Now, we do 1 from the left added on to one from the right, and get 101(2+99). Then, we can follow that pattern and do 3+98=101, 4+97=101, and as long as we follow that pattern, we keep getting 101 as our answer.

Now, if we keep going with this, eventually we will get to 48+53, 49+52, 50+51.

If we supposedly counted all these pairs, we would find we have 50 pairs. But a quick way to check is to just divide 100 by 2 (100/2) and we get 50.

Now, we have 50 pairs that add up to 101. So, that would be 101 added to itself 50 times, which is just multiplication. 101 × 50 which is 5050.

I hope this helped. Let me know if you have any questions.

pshichka [43]3 years ago
5 0
The answer is 91 integers
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3 years ago
James earned $39,600 last year. He paid $11,250 towards rent and $1,422 in car payments. What percent of his earnings did Jon pa
tester [92]
Step 1:
Add rent & car payments

=11,250+1422
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Step 2:
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12,672/39,600 = x/100
cross multiply
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OR

Alternative Step 2:
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or move decimal to the right 2 places

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3 years ago
Read 2 more answers
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Answer:

10

Step-by-step explanation:

If n = 11 and p = 5, we can just substitute the values in for n and p in the equation 18 - n - 2 + p.


The new equation would be 18 - 11 - 2 + 5.

Using PEMDAS, we get the answer of 10.  

18 - 11 = 7

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Hope this helps!

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