The scalar reading during the process is 170. 5 Newton
<h3>
How to determine the scalar reading</h3>
force = mass × acceleration
Given the mass = 55kg
In finding the acceleration, use the first equation of motion
v = u + at
u = 0
t = 2s
v = 6.5 m/s
Substitute the values
6.5 = 0 + 2a, make 'a' the subject
a = 6. 5÷ 2 = 3. 1 m/s²
Substitute the value of 'm' and 'a' in the original equation
F = 55× 3.1 = 170. 5 Newton
Hence, the scalar reading during the process is 170. 5 Newton
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Simple: if a charge is positive, it loses electrons. If negative, it gains.
Answer:
53.64 m/s
Explanation:
Applying,
a = (v-u)/t............. Equation 1
Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
make u the subject of the equation
u = v-at............. Equation 2
From the question,
Given: a = -12 mph/s = -5.364 m/s², t = 10 seconds, v = 0 m/s (comes to stop)
Substitute these values into equation 2
u = 0-(-5.364×10)
u = 0+53.64
u = 53.64 m/s
I believe the correct answer from the choices listed above is option 3. The work done by the student to the book would be 50 J. T<span>he </span>work done<span> by gravity is simply the force of gravity times the displacement. That is 25N x 2 m and is equal to 50 J. Hope this answers the question.</span>
