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bekas [8.4K]
3 years ago
14

A ball is projected vertically upward from the surface of the Earth with an initial speed of +49 meters per second. The ball rea

ches its maximum height in 5.0 seconds. What is the maximum height reached by the ball?
Physics
1 answer:
fenix001 [56]3 years ago
8 0
Answer: 245 meters

Explanation: 49 ? Meters
over over over
1 5 seconds

Cross multiply- 49 times 5 divided by 1 which equals 245
You might be interested in
g what are the bands of electromagneitc radiation and how are they related to energy frequency and wavelength
ch4aika [34]

Answer:

The details of bands is given in explanation.

Explanation:

The electromagnetic waves are differentiated into different bands based upon their wavelengths and frequencies. The names of different bands are as follows:

1. Radio Waves

2. Micro Waves

3. Infra-red

4. Visible light

5. Ultra Violet

6. X-rays

7. Gamma Rays

<u>The frequency of every region or rays increases from 1 through 7</u>. The <u>energy of rays also increase from 1 through 7</u>. Since, the wave length is inversely related to energy and frequency, thus the <u>wavelength of rays decrease from 1 through 7</u>.

A detailed information of the bands is provided in the picture attached.

3 0
3 years ago
Tom Cruise jumped from one building to other building while filming the roof chase scene in Mission: Impossible - Fallout. He di
OLga [1]

Answer:

v_0=9.9\ m.s^{-1}

Explanation:

Given:

  • angle of launch of projectile from horizontal, \theta=15^{\circ}
  • range of projectile, R=5\ m

<u>We have formula  for the range of projectile:</u>

R=\frac{v_0^2\times sin\ 2\theta}{g}

putting the respective values

5=\frac{v_0^2\times sin\ 30^{\circ}}{9.8}

v_0=9.9\ m.s^{-1} is the velocity with which Tom should jump to land on the other roof.

3 0
3 years ago
Arrow_forward
garri49 [273]

Explanation:

(a) Hooke's law:

F = kx

7.50 N = k (0.0300 m)

k = 250 N/m

(b) Angular frequency:

ω = √(k/m)

ω = √((250 N/m) / (0.500 kg))

ω = 22.4 rad/s

Frequency:

f = ω / (2π)

f = 3.56 cycles/s

Period:

T = 1/f

T = 0.281 s

(c) EE = ½ kx²

EE = ½ (250 N/m) (0.0500 m)²

EE = 0.313 J

(d) A = 0.0500 m

(e) vmax = Aω

vmax = (0.0500 m) (22.4 rad/s)

vmax = 1.12 m/s

amax = Aω²

amax = (0.0500 m) (22.4 rad/s)²

amax = 25.0 m/s²

(f) x = A cos(ωt)

x = (0.0500 m) cos(22.4 rad/s × 0.500 s)

x = 0.00919 m

(g) v = dx/dt = -Aω sin(ωt)

v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)

v = -1.10 m/s

a = dv/dt = -Aω² cos(ωt)

a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)

a = -4.59 m/s²

3 0
3 years ago
A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic
Umnica [9.8K]

Answer:

<em>A = 6.9 cm</em>

Explanation:

<u>Simple Harmonic Motion</u>

A mass-spring system is a common example of a simple harmonic motion device since it keeps oscillating when the spring is stretched back and forth.

If a mass m is attached to a spring of constant k and they are set to oscillate, the angular frequency of the motion is

\displaystyle w=\sqrt{\frac{k}{m}}

The equation for the motion of the object is written as a sinusoid:

\displaystyle X=A\ cos\ w\ t

Where A is the amplitude.

The instantaneous speed is computed as the derivative of the distance

\displaystyle X'=V=-A\ w\ sin\ w\ t

And the maximum speed is

\displaystyle V_{max}= A\ w

Solving for the amplitude

\displaystyle A= \frac{V_{max}}{w}

Computing w

\displaystyle w =\sqrt{\frac{120}{0.2}}=24.5\   rad/ s

Calculating A

\displaystyle A=\frac{1.7}{24.5}=0.069\ m

\displaystyle \boxed{A=6.9\ cm}

7 0
3 years ago
Describe the advantages and disadvantages of keeping the road clear of ice
harina [27]
A advantage is less car accidents and a disadvantage is, in order to keep the roads clear of ice is a chemical. Like salt. Which is bad for the animals.
4 0
3 years ago
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