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galben [10]
3 years ago
11

Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?

Physics
2 answers:
Svetradugi [14.3K]3 years ago
7 0

Answer:

The volume of the sample is 10\ cm^3

Explanation:

It is given that,

Frank has a sample of steel that weighs 80 grams

The density of his sample of steel is d=8\ g/cm^3

We have to find the volume of the sample. Density of an object is defined as mass per unit volume i. e.

d=\dfrac{m}{V}

V=\dfrac{m}{d}

V=\dfrac{80\ g}{8\ gm/cm^3}

V=10\ cm^3

Hence, the volume of the sample is 10\ cm^3

FrozenT [24]3 years ago
6 0
Should be 10 cm cubed
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Vera_Pavlovna [14]

Answer:

option B

Explanation:

When a body is immersed in liquid there will be two force is acting on the body.

First one force acting downward due to weight of the body.

And the second force acting on the object will be buoyant force.

If the object is not in equilibrium the apparent weight will be equal to net force acting on the object.

     F_{net} = W - F_b

W is the weight of the object acting downward

Fb is the buoyancy force acting upward on the object.

Hence, the correct answer is option B

3 0
3 years ago
The Volts are the ________________
Vera_Pavlovna [14]
People who went out and sailed on the sea and then they went on missions
8 0
3 years ago
A printer is connected to a 1.0 m cable. if the magnetic force is 9.1 × x10-5 n, and the magnetic field is 1.3 × 10-4 t, what is
Valentin [98]
The magnetic force on a current-carrying wire due to a magnetic field is given by
F=ILB
where
I is the current
L the wire length
B the magnetic field strength

In our problem, L=1.0 m, F=9.1 \cdot 10^{-5} N and B=1.3 \cdot 10^{-4}T, so we can re-arrange the formula to find the current in the wire:
I= \frac{F}{LB}= \frac{9.1 \cdot 10^{-5} N}{(1.0 m)(1.3 \cdot 10^{-4} T)} =0.7 A
5 0
3 years ago
What is the concentration of H^ + at apH = 2 ? Mol / L What is the concentration of H^ + ions at apH = 6 ? Mol/L How many more H
Nonamiya [84]

Answer:

The concentration of hydrogen ion at pH is equal to 2 := [H^+]=0.01 mol/L

The concentration of hydrogen ion at pH is equal to 6 : [H^+]'=0.000001 mol/L

There are 0.009999 more moles of  H^+ ions in a solution at a pH = 2 than in a solution at a pH = 6.

Explanation:

The pH of the solution is the negative logarithm of hydrogen ion concentration in an aqueous solution.

pH=-\log [H^+]

The hydrogen ion concentration at pH is equal to 2 = [H^+]

2=-\log [H^+]\\

[H^+]=10^{-2}M= 0.01 M=0.01 mol/L

The hydrogen ion concentration at pH is equal to 6 = [H^+]

6=-\log [H^+]\\\\

[H^+]=10^{-6}M= 0.000001 M= 0.000001 mol/L

Concentration of hydrogen ion at pH is equal to 2 =[H^+]=0.01 mol/L

Concentration of hydrogen ion at pH is equal to 6 = [H^+]'=0.000001 mol/L

The difference between hydrogen ion concentration at pH 2 and pH 6 :

= [H^+]-[H^+]' = 0.01 mol/L- 0.000001 mol/L = 0.009999 mol/L

Moles of hydrogen ion in 0.009999 mol/L solution :

=0.009999 mol/L\times 1 L=0.009999 mol

There are 0.009999 more moles of  H^+ ions in a solution at a pH = 2 than in a solution at a pH = 6.

8 0
2 years ago
PLEASE HELP!!
dedylja [7]
Pretty sure it’s A. Hope this helps.
4 0
2 years ago
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