Convert 100° to radians. Will mark brainlist if correct

What is StartFraction 4 Over 5 EndFraction divided by one-third A fraction bar. The top bar is labeled 1. 3 bars underneath the

Vladimir79 [104]

Answer:

2 2/5

Step-by-step explanation:

Given 4/5÷1/3

Multiply 4/5 with the reciprocal of 1/3 as shown;

= 4/5 × 1/(1/3)

= 4/5 × 3/1

= 12/5

= 2 2/5

The quotient is 2 2/5

4 0

3 years ago

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A truck that is 12 ft. by 10 ft. by 15 ft. carries cube

kvasek [131]

Answer: 284 boxes in the shape of the cubes can be fitted in the truck.

Step-by-step explanation:

If a truck is fitted fully with the cubes, volume of the truck will be equal to the volume of cubes to be fitted.

Dimensions of the truck given in the question,

Length = 10 feet, width = 12 feet and height = 8 feet

Since, volume of a cuboid (shape of a truck) is given by the expression,

Volume = Length × Width × Height

Therefore, volume of the truck = 10 × 12 × 8

= 960 feet³

Volume of a cube is given by the expression,

Volume = (side)³

Therefore, volume of the cube with side length 1.5 feet will be,

Volume of a cube = (1.5)³

= 3.375 cubic feet

Let the number of cubes fitted in the truck = x

Therefore, volume of 'x' cubes = (3.375x) feet³

Since, volume of the truck = Volume of the cubes fitted

3.375x = 960

x = 960/3.375

x = 284.44

x ≈ 284

Therefore, 284 boxes in the shape of the cubes can be fitted in the truck.

5 0

1 year ago

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How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below