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lapo4ka [179]
3 years ago
14

A. Among nonpolar liquids, those with higher molar masses tend to have normal boiling points that are (higher, lower, or about t

he same).
b. Among compounds of approximately the same molar mass, those with greater polarities tend to have enthalpies of vaporization that are (higher, lower, or about the same).
c. Which is the only noble gas listed that is stable as a liquid at 0°C? Explain your answer using the concept of critical temperature.

Chemistry
2 answers:
kirill [66]3 years ago
8 0

Answers are below...and I have answered this question on the basis of above table.

Explanation :-

(a.) Among nonpolar liquids, those with higher molar masses tend to have normal boiling points that are (lower).

(b.) Among compounds of approximately the same molar mass, those with greater polarities tend to have enthalpies of vaporization that are (higher).

(c.) Xe (Xenon), a substance can exist only as a gas at temperatures above its critical temperature. Of the noble gases listed, only Xe has a critical temperature above O°c.

lana66690 [7]3 years ago
6 0

Answer: higher b. Among compounds of approximately the same molar mass, those with greater polarities tend to have Wiesenthal of vaporization that are (higher, lower.

Explanation: Molecules in a gas are far apart. They are mulct"\ closer together in a liquid. Molecules in a gas are easily squeezed closer together as the gas is compressed and walls more frequently than before and with a greater force per impact.

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Mixtures are made up of what substances.
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A 3.689 g object is added to 7.29 mL of water causing The water level to rise to 8.54 ML. What is the density of the object? Rou
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Answer:

2.95 g / mL

Explanation:

For this problem, we will simply use the equation that density is equivalent to mass over volume.  We are given the mass of the object and the initial and final volumes of water in the cylinder.  Thus we can find the density as such:

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4 years ago
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Answer:

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General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

5.72 g FeCl₂

<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

<u />5.72 \ g \ FeCl_2(\frac{1 \ mol \ FeCl_2 }{126.75 \ g \ FeCl_2} ) = 0.045128 mol FeCl₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.045128 mol FeCl₂ ≈ 0.0451 mol FeCl₂

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