Ask question

Ask question

All categories

2 years ago

11

In the following reaction, what coefficient will be written before the oxygen molecule (O2) to balance the chemical equation? (1

point) _____ C5H12 + _____ O2 _____ CO2 + _____ H2O

2 answers:

faust18 [17]2 years ago

4 0

It would look like:
C5H12+ 8O2 ==> 5CO2 + 6H2O

Sergeu [11.5K]2 years ago

3 0

Should be C5H12 + 8O2 yields 5CO2 + 6H2O

You might be interested in

What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi

Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0

3 years ago

The specific heat of water is 4.186 J/g°C. A sample of 40. g H subscript 2 O is at an initial temperature of 91.0 °C. If the sam

kati45 [8]

The is 83 degrees outside

7 0

3 years ago

An element has five isotopes. Calculate the atomic mass of this element using the information below. Show all your work. Using t

Katena32 [7]

Answer: Sol:-

Data provided in the question is :-

Atomic mass of isotope -1 = 64 amu

Atomic mass of isotope -2 = 66 amu

Atomic mass of isotope -3 = 67 amu

Atomic mass of isotope -4 = 68 amu

Atomic mass of isotope - 5 = 70 amu

Percentage abundace of isotope - 1 = 48.89 %

Percentage abundance of isotope -2 = 27.81 %

Percentage abundance of isotope - 3 = 4.11%

Percentage abundance of isotope-4 = 18.57%

Percentage abundance of isotope - 5 = 0.62 %

Formula used :-

Average atomic mass of an element =[ {(atomic mass of isotope-1 * percentage abundance of isotope-1) + ( atomic mass of isotope-2 * percentage abundance of isotope -2) + ( atomic mass of isotope -3 * percantege abundance of isotope-3 ) + ( atomic mass of isotope-4 * percentage abundance of isotope-4) + (atomic mass of isotope-5 * percentage abundance of isotope-5)} / 100]

Calculation :-

Put all the value in the formula :-

Average atomic mass of an element = [{(64 * 48.89) + (66 * 27.81) + (67 * 4.11) + (68 * 18.57) + (70 * 0.62)} / 100] amu

= [{(3128.96) + (1835.46) +(257.37) + (1262.76) + (43.4)} / 100] amu

= {(6528.04) / 100} amu

= 65.2804 amu

Average atomic mass of an element is = 65.2804 amu

Then this mass is approximatly equal to atomic mass of zinc so this element would be zinc

atomic mass of zinc = 65.38 \approx 65.2804 amu

5 0

2 years ago

Of these four liquids, which is the most viscous?

Iteru [2.4K]

I believe the correct answer from the choices listed above is the last option. <span>Of these four liquids, the most viscous one is honey at room temperature. Honey is made up of sugars and the hydrogen of the sugars and water is what makes it more viscous.</span>

6 0

3 years ago

Read 2 more answers

If the mass of a material is 40 grams and the volume of the material is 9 cm^3, what would the density of the material be?

solniwko [45]

Mass = m = 40 grams
Volume = V = 9 cm³
Density = d = ?

Density is defined as the ratio of mass and volume.

So,

d = m/V

Using the values, we get

d = 40/9 = 4.44 g/cm³

This means the density of material would be 4.44 g/cm³

3 0

2 years ago