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satela [25.4K]
3 years ago
7

How can two objects of similar shape and size have different densities

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
3 0
The mass and Volume is different even thought they have a similar shape and size
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Do you think that every substance can be separated physically or chemically into other substances? Explain your answer.
Olegator [25]

Answer:

Chemical Substances

It cannot be separated into components without breaking chemical bonds. Chemical substances can be solids, liquids, gases, or plasma. Changes in temperature or pressure can cause substances to shift between the different phases of matter.

Explanation:

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6 0
3 years ago
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3. The basic unti of matter *<br> proton<br> neutron<br> electron<br> atom
mamaluj [8]

Answer:

Your answer is ATOM

Explanation:

Atoms consist of a nucleus made of protons and neutrons orbited by electrons. Atoms are the basic units of matter and the defining structure of elements.

Basically, they are the building block of life because everything made of matter has atoms

8 0
3 years ago
g Alkenes and alkynes are called unsaturated compounds because ________. they have fewer hydrogen atoms attached to the carbon c
Firdavs [7]

Answer:

They have fewer hydrogen atoms attached to the carbon chain than alkanes

Explanation:

Let's compare ethane (an alkane) with ethene (an alkene) and ethyne (an alkyne):

  • Ethane's formula is C₂H₄, while ethene's is C₂H₄ and ethyne's C₂H₂.

As you can see, alkenes and alkynes have fewer hydrogen atoms attached to the carbon chain due to them having multiple bonds between the carbon atoms.

7 0
3 years ago
How much energy in kilojoules is released when 23.4 g of ethanol vapor at 83.0 ∘C is cooled to -15.0 ∘C ?
slamgirl [31]

Answer : The amount of in kilojoules released is, -5.53 kJ

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat released = ?

c = specific heat of ethanol = 2.41J/g^oC

m = mass of ethanol = 23.4 g

T_{final} = final temperature = -15.0^oC

T_{initial} = initial temperature = 83.0^oC

Now put all the given values in the above formula, we get:

q=23.4g\times 2.41J/g^oC\times (-15.0-83.0)^oC

q=-5526.612J=-5.53\times 10^3J=-5.53kJ

Therefore, the amount of in kilojoules released is, -5.53 kJ

5 0
4 years ago
96 K = _____ -177°C 0°C 96°C 369°C
velikii [3]
ºC = K - 273

ºC = 96 - 273

= -177ºC

answer A

hope this helps!
6 0
3 years ago
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