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eduard
3 years ago
5

IS THERE LIFE ON MARS? A random sample of 160 scientists is asked whether they believe that life once existed on Mars. Eight of

them do, and 152 do not. If the true proportion of scientists who believe life once existed on Mars is 5%, what is the probability of eight or fewer answering "yes" in a sample of this size? What sampling distribution(s) can we use to compute this probability?
Mathematics
1 answer:
fiasKO [112]3 years ago
6 0

Answer:

No because there isn’t enough oxygen in mars in order for someone to live,I believe in my references

Step-by-step explanation:

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Please help thank you.
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Question 1:

To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.

A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram. 

A square has 4 right angles, so it's also a rectangle.

A square has 4 sides, so it's also a quadrilateral.

The first choice is your answer.

Question 2:

Not all quadrilaterals are rectangles, so A is incorrect.

Not all quadrilaterals are squares, so B is incorrect.

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Thus, C is your answer.

Question 3: 

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Have an awesome day! :)
7 0
3 years ago
Write 26% as a decimal.
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6 0
2 years ago
In 1-5, given: Two similar cylinders with heights of 8 and 5 respectively.
lana66690 [7]

Answer:

1. The ratio of their diameters is 8/5 = 8 : 5

2. The ratio of their surface area is (8/5)²

3. The ratio of their volume is (8/5)³

4.The area of the base of the larger cylinder is 128 cm²

Step-by-step explanation:

Given that the two cylinders are similar, we have;

Two cylinders are similar when the ratio of their heights is equal to the ratio of their radii

Therefore, we have;

1. The ratio of the height of the two cylinders = 8/5 = The radio of their radii = r₁/r₂

The ratio of their diameter = D₁/D₂ = 2·r₁/2·r₂ = r₁/r₂ = 8/5

The ratio of their diameters D₁/D₂ = 8/5 = 8 : 5

2. The surface area of the cylinders = 2·π·r·h + 2·π·r²

Therefore, we have;

(2·π·r₁·h₁ + 2·π·r₁²)/(2·π·r₂·h₂ + 2·π·r₂²) = (r₁·h₁ + r₁²)/(r₂·h₂ + r₂²)

h₁ = h₂ × 8/5

r₁ = r₂ × 8/5

= (8/5)²(r₂·h₂ + r₂²)/(r₂·h₂ + r₂²)  = (8/5)²

The ratio of their surface area = (8/5)²

3. The volume of the cylinder = π·r²·h

∴ The ratio of the volume = (π·r₁²·h₁)/(π·r₂²·h₂) = (8/5)³ × (π·r₂²·h₂)/(π·r₂²·h₂) = (8/5)³

The ratio of their volume = (8/5)³

4. The ratio of the area of the base of the larger cylinder to the area of the base of the smaller cylinder is (8/5)²

Therefore if the area of the base of the smaller cylinder is 50 cm², the area of the base of the larger cylinder = 50 cm² × (8/5)²  = 128 cm²

7 0
2 years ago
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