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Aleks [24]
3 years ago
7

The diagram shows the diameter of the opening

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0

Answers

D 36

Step-by-step explanation:

77 is the area for the squared trapezoid and 36 is the closest to 77

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Write an equation for line L in point-slope form and slope-intercept form.
Marianna [84]

Answer:

y = -\frac{1}{4}x + c --- Slope intercept

y - y_1 = -\frac{1}{4}(x - x_1) --- Point slope

Step-by-step explanation:

Given

Perpendicular to y = 4x

Required

Determine its equation

The general form of an equation is:

y = mx + c

Where

m = slope

By comparison:

m = 4

Next, we calculate the slope of L.

Because L is perpendicular to y = 4x, the relationship between their slopes is:

m_2 = -\frac{1}{m}

Substitute 4 for m

m_2 = -\frac{1}{4}

The equation of L in slope intercept form is: y = mx + c

Substitute -1/4 for m

y = -\frac{1}{4}x + c

In point slope form, we have:

y - y_1 = m(x - x_1)

Substitute -1/4 for m

y - y_1 = -\frac{1}{4}(x - x_1)

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2 years ago
Brian filled his ½ cup measuring cup 5 times to have enough flour for a cake recipe. How much flour does the cake recipe call fo
Alisiya [41]
Answer: 2 1/2 cups of flour
5 0
3 years ago
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larisa86 [58]
The rock hits the gorund at 45s. is the answer
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3 years ago
The populations of termites and spiders in a certain house are growing exponentially. The house contains 120 termites the day yo
zysi [14]

Answer:

in order to triple the inicial population of spiders, will take 50395 days

Step-by-step explanation:

we can define the termite population function as T(t) and the one for spiders as S(t) , where t represents time measured in days

since both have and exponencial growth

T(t)= a*e^(b*t)

S(t)= c*e^(d*t)

1) when the day the person moves in , t=0 and T(0)= 120 termites

T(0) = a*e^(b*0) = a = 120

2) after 4 days , t=4 and  the house contains T(4) = 210 termites

T(4)= 120*e^(b*4) = 210 → 4*b = ln (210/120) → b = (1/4)* ln(210/120)= 0.14

therefore

T(t) = 120*e^(0.14*t)

3) 3 days after moving in , t=3, there were T(3) = 120*e^(0.14*3)=182.63≈ 182 termites . The number of spiders is half of the number of termites → S(3) = T(3) * 1 spider/ 2 termites  =91.31 spiders ≈ 91 spiders

4) after 8 days of moving in , t=8, there were T(8) = 120*e^(0.14*8)=367.78≈ 368 termites . The number of spiders is 0.25 times the number of termites → S(8) = T(8) * 1 spider/ 4 termites =91.94 spiders   ≈ 92 spiders

from

S(t)= c*e^(d*t) → d = ln [S (tb)/S (ta) ] / (tb-ta)

therefore d = ln [ S(8)/S(3) ] / (8 - 3 ) = 2.18*10^-5

in order to triple the initial population

S(t3) = 3 *S(0) = 3*[c*e^(d*0)] = 3*c

S(t3) = c*e^(d*t3) = 3* c → t3 = ln(3) / d = 50395 days

5 0
3 years ago
Draw the image ABC under a translation by 3 units to the left and 3 units down​
juin [17]

Answer:

so basicaly on this one bring the line down 3 units and 3 unit to the left it is really easy

Step-by-step explanation:

4 0
3 years ago
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