Answer:
Step-by-step explanation:
Three eights
Answer:
The measurement of angle a is 42.5°
The measurement of angle b is 19.5°
Step-by-step explanation:
Angle a = a
Angle b = b
m < a + m < b = 62°
"m <" means "measurement of angle..."
m < a + m < b = 4m < a - 108°
Subtract m < a from both sides of the equation
m < b = 4m < a - 108° - m < a
Simplify
m < b = 3m < a - 108°
Substitute into original equation
3m < a - 108° + m < a = 62°
Add m < a + 3m < a
4m < a - 108° = 62°
Add 108° to both sides of the equation
4m < a = 170°
Divide both sides of the equation by 4
m < a = 42.5°
m < b = 62° - 42.5° = 19.5°
Hope this helps :)
Answer:
x = -7
Step-by-step explanation:
6/x + 8/x + 5 =3
5x + 14 /x =3
Step 1: Multiply both sides by x.
5x+14=3x
5x+14−3x=3x−3x(Subtract 3x from both sides)
2x+14=0
2x+14−14=0−14(Subtract 14 from both sides)
2x=−14
2x
2
=
−14
2
(Divide both sides by 2)
x=−7
Check answers. (Plug them in to make sure they work.)
x=−7(Works in original equation)
There should be a point the line is going through, (1,2).
We have given that,
N55.60 for 1yr 6 months at the rate of 2%
We have to determine the principal which will yield simple interest of N55.60 for 1yr 6 months at the rate of 2%.
<h3>
What is the simple interest?</h3>
A = final amount
P = initial principal balance
r = annual interest rate
t = time (in years)
x = inches
y = miles
per 1 inch = 2 miles
so on the graph, there should be a point the line is going through, (1,2).
To learn more about the simple interest visit:
brainly.com/question/2294792
#SPJ2
Answer:
In inequality notation:
Domain: -1 ≤ x ≤ 3
Range: -4 ≤ x ≤ 0
In set-builder notation:
Domain: {x | -1 ≤ x ≤ 3 }
Range: {y | -4 ≤ x ≤ 0 }
In interval notation:
Domain: [-1, 3]
Range: [-4, 0]
Step-by-step explanation:
The domain is all the x-values of a relation.
The range is all the y-values of a relation.
In this example, we have an equation of a circle.
To find the domain of a relation, think about all the x-values the relation can be. In this example, the x-values of the relation start at the -1 line and end at the 3 line. The same can be said for the range, for the y-values of the relation start at the -4 line and end at the 0 line.
But what should our notation be? There are three ways to notate domain and range.
Inequality notation is the first notation you learn when dealing with problems like these. You would use an inequality to describe the values of x and y.
In inequality notation:
Domain: -1 ≤ x ≤ 3
Range: -4 ≤ x ≤ 0
Set-builder notation is VERY similar to inequality notation except for the fact that it has brackets and the variable in question.
In set-builder notation:
Domain: {x | -1 ≤ x ≤ 3 }
Range: {y | -4 ≤ x ≤ 0 }
Interval notation is another way of identifying domain and range. It is the idea of using the number lines of the inequalities of the domain and range, just in algebriac form. Note that [ and ] represent ≤ and ≥, while ( and ) represent < and >.
In interval notation:
Domain: [-1, 3]
Range: [-4, 0]
