Solve for F. C= 5/9 (F-32)

Mathematics

1 answer:

Korvikt [17]4 years ago

6 0

F-32 =C÷5/9
F-32 = C(9/5) = 9/5C
F = 9/5C + 32

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Luden [163]

Answer:

Cost of five blouses = $145

Step-by-step explanation:

Let

x = cost of blouse

y = cost of skirt

15x + 2y = 505 (1)

5x + 2y = 215 (2)

Subtract (2) from (1) to eliminate y

15x - 5x = 505 - 215

10x = 290

x = 290/10

x = 29

Substitute x = 29 into (2)

5x + 2y = 215 (2)

5(29) + 2y = 215

145 + 2y = 215

2y = 215 - 145

2y = 70

y = 70/2

y = 35

x = cost of blouse = $29

y = cost of skirt = $35

How much do 5 such blouses cost?

cost of a blouse = $29

Cost of five blouses = $29 × 5

= $145

Cost of five blouses = $145

5 0

3 years ago

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Mademuasel [1]

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4 0

3 years ago

How do I solve these problems?

lesya [120]

$Domain:\\D:x > 0\\\\\ln x=5.6+\ln(7.5)\ \ \ \ |-\ln(7.5)\\\\\ln x-\ln7.5=5.6\ \ \ |Use\ \log x-\log y=\log\dfrac{x}{y}\\\\\ln\dfrac{x}{7.5}=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\\dfrac{x}{7.5}=e^{5.6}\ \ \ \ |\cdot7.5\\\\\boxed{x=7.5e^{5.6}}\in D$

$\log x=5.6-\log7.5\ \ \ \ |+\log7.5\\\\\log x+\log7.5=5.6\ \ \ \ |use\ \log x+\log y=\log (xy)\\\\\log(7.5x)=5.6\ \ \ \ |use\ \log_ab=c\iff a^c=b\\\\7.5x=10^{5.6}\ \ \ \ |:7.5\\\\\boxed{x=\dfrac{10^{5.6}}{7.5}}\in D$