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PilotLPTM [1.2K]
3 years ago
5

anna has $50.00 in the bank. she adds $5.00 in the first week,$10.00 in the second week,and $15.00 in thr third week. at this ra

te, how much money will she have in the bank at the end of 6 weeks
Mathematics
1 answer:
Ronch [10]3 years ago
5 0
At the end of six weeks, she would have $155 in the bank. At this rate, the expression is as follows: $5 + $10 + $15 + $20 + $25 + $30 = $105. Because she already had $50 in the bank, that is another $50 added to the total. This gives the answer $155.
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Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

8 0
3 years ago
Asher pays 156 every 6 weeks for piano lessons what is the price per year for piano lessons
Anna [14]
356 days in a year / 7 days in a week = 50.8 weeks in a year

50.8 weeks in a year / 6 weeks = 8.48 payments

$156 x 8.48 payments = $1322.88 per year
6 0
3 years ago
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