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3 years ago

7

Simplify the following completely, show all work.4 + ✓-27

1 answer:

V125BC [204]3 years ago

8 0

Answer:

4+3i $\sqrt{3}$

Step-by-step explanation:

the $\sqrt{-27}$ needs to be simplified

first, I broke it down to $\sqrt{-1}$ and $\sqrt{27}$

$\sqrt{-1}$ simplifies to i ;and can be broken down to $\sqrt{9}$ and $\sqrt{3}$

$\sqrt{9}$ can be simplified further to 3

Now all you have to do is put it together

4(which you didnt have to do anything to)+ 3i( 3 from the sqrt of 9 and i from the sqrt of -1) sqrt 3( which cant be simplified further)

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Subtract 5x^2 – 2x – 5 from – 2x^2<br> - 5x - 7

user100 [1]

Answer:

$-7x^{2} -3x-2$

Step-by-step explanation:

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Please answer these 2 questions. I promise to mark as brainliest if you can solve with steps. Thank you.

neonofarm [45]

Answer:

see explanation

Step-by-step explanation:

4

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{BC}{EF}$ = $\frac{AB}{DE}$ ( substitute in values )

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The parallel line segment SV is half of RW

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3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

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$S=2\pi rh$

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h = height,

Given,

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$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

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$S=2\pi r(\sqrt{16-4r^2})$

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$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

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Again differentiating with respect to r,

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Anna35 [415]

Answer:

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3 9

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