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asambeis [7]
4 years ago
15

Create a problem that would have the answer 3x+12

Mathematics
1 answer:
oee [108]4 years ago
7 0

Answer:

Problem:

Consider a rectangle such that the length of the rectangle is 12 more than thrice its width. Find a formula for the length in terms of its width. Take width as 'x'.

Step-by-step explanation:

Consider a rectangle such that the length of the rectangle is 12 more than thrice its width. Find a formula for the length in terms of its width.

Let the width be 'x'.

Therefore, as per question, length is 12 more than thrice the width.

Thrice the width means 3x. 12 more means adding 12 to the result.

Therefore, the length of the rectangle is 3x+12

So, the above question expresses the length of the rectangle as 3x+12 which is the required answer.

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The slope of a hill is an average of 0.64. How
Novosadov [1.4K]

Answer: rise = 20.48m = X

:Percent Grade = 0.048 x 100%

= 4.8%

5 0
3 years ago
PLEASE HELP ME ASAP????? <br><br> What is the area of rectangle PQRS
Molodets [167]

Answer:

The area of this rectangle is: 91cm^{2}

Step-by-step explanation:

The formula for the area of a rectangle is : length * width

To work this out you would simply multiply the length of 14 by the width of 6.5, which gives you 91cm^{2}.

Remember when working out the area of any shape the answer will always be in the unit squared.

1) Multiply 14 by 6.5.

14*6.5=91cm^{2}

3 0
3 years ago
The measure of ∠BCD is 120°. The measure of ∠ABC is 85°.
saveliy_v [14]

Answer:

Step-by-step explanation:

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Lay back, it's all been done before

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I like you the way you are

When we're driving in your car

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4 0
3 years ago
Solve the equation for x 120(2x − 2) = 240
sashaice [31]

Answer:

The answer is 2

Step-by-step explanation:

To find this, follow the order of operations as laid out below.

120(2x - 2) = 240 ----> Divide both sides by 120

2x - 2 = 2 ----> Add 2 to both sides

2x = 4 ------> Divide both sides by 2

x = 2

5 0
4 years ago
Read 2 more answers
Find a parabola with equation y = ax2 + bx + c that has slope 5 at x = 1, slope −11 at x = −1, and passes through the point (2,
azamat

By "slope" I assume you mean slope of the tangent line to the parabola.

For any given value of <em>x</em>, the slope of the tangent to the parabola is equal to the derivative of <em>y</em> :

y=ax^2+bx+c\implies y'=2ax+b

The slope at <em>x</em> = 1 is 5:

2a+b=5

The slope at <em>x</em> = -1 is -11:

-2a+b=-11

We can already solve for <em>a</em> and <em>b</em> :

\begin{cases}2a+b=5\\-2a+b=-11\end{cases}\implies 2b=-6\implies b=-3

2a-3=5\implies 2a=8\implies a=4

Finally, the parabola passes through the point (2, 18); that is, the quadratic takes on a value of 18 when <em>x</em> = 2:

4a+2b+c=18\implies2(2a+b)+c=10+c=18\implies c=8

So the parabola has equation

\boxed{y=4x^2-3x+8}

6 0
3 years ago
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