Answer:
y = 1m - 1
Step-by-step explanation:
Let's assume
number of small notebooks =x
number of large notebooks =y
we are given
total number of notebooks =31
so, we get
![x+y=31](https://tex.z-dn.net/?f=%20x%2By%3D31%20)
now, we can solve for y
![y=31-x](https://tex.z-dn.net/?f=%20y%3D31-x%20)
we have
Small notebooks cost $3.50 and large notebooks cost $5.00
she has $134 to spend
so, we get
![3.50x+5y=134](https://tex.z-dn.net/?f=%203.50x%2B5y%3D134%20)
now, we can plug y
![3.50x+5(31-x)=134](https://tex.z-dn.net/?f=%203.50x%2B5%2831-x%29%3D134%20)
![3.50x+5*31-5x=134](https://tex.z-dn.net/?f=%203.50x%2B5%2A31-5x%3D134%20)
![-1.5x+155=134](https://tex.z-dn.net/?f=%20-1.5x%2B155%3D134%20)
![-1.5x+155-155=134-155](https://tex.z-dn.net/?f=%20-1.5x%2B155-155%3D134-155%20)
![x=14](https://tex.z-dn.net/?f=%20x%3D14%20)
now, we can find y
![y=31-14](https://tex.z-dn.net/?f=%20y%3D31-14%20)
![y=17](https://tex.z-dn.net/?f=%20y%3D17%20)
so,
number of small notebooks is 14
number of large notebooks is 17.............Answer
The coefficient is 4
The constants are 2 and 3
The answer might be 3.5 because i am pretty sure it is not a repeating decimal
<u>(2 x y) </u>is a factor of (6 x y), so it's the highest common factor of both expressions.