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AleksAgata [21]
3 years ago
9

A system of linear equations includes the line that is created by the equation y = x+ 3, graphed below, and the line through the

points (3, 1) and (4, 3).
On a coordinate plane, a line goes through (0, 3) and (2, 5).
What is the solution to the system of equations?

Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

  (8, 11)

Step-by-step explanation:

The 2-point form of the equation of a line is useful for the one where only points are given.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (3 -1)/(4 -3)(x -3) +1

  y = 2(x -3) +1

We can equate this to the expression for y in the given equation.

  x +3 = 2(x -3) +1

  x +3 = 2x -5 . . . . . . eliminate parentheses

  8 = x . . . . . . . . . . . . add 5-x

Using the given equation, we can find y:

  y = x +3 = 8 +3

  y = 11

The solution to the system is (x, y) = (8, 11).

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To rationalize the denominator 2 sqrt 10/ 3 sqrt 11 you should multiply the expression by which fraction
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Answer:

B

Step-by-step explanation:

To rationalise the denominator.

Multiply the numerator/denominator by the radical on the denominator.

The radical on the denominator is \sqrt{11}, thus

Multiply the fraction by

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3 years ago
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A probability experiment will consist of selecting one of two stacks of cards, and then choosing a card at random from the stack
postnew [5]

Answer:

The probability that the red card came from the first stack is:

40%

Step-by-step explanation:

a) Data and Calculations:

Stack         Red      Blue   Total

First            6           5         11

Second      9            0         9

Total         15            5       20

The probability of selecting from the first stack = 50% since equal opportunity is given to the two sacks.

The probability of red card from the first stack = 6/15 = 0.4 = 40%.

b) The probability that the red card came from the first stack is given by the number of red cards in the first stack divided by the number or red cards in the two stacks.  This is equal to 6/15 = 0.4 or 40%.

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2 years ago
During a cold winter, the temperature stayed below zero for 10 days (ranging from −20 to −5). The variance of the temperatures o
Serjik [45]

Answer:

The variance of the temperatures of the 10 day period must be at least zero.

Step-by-step explanation:

The variance is the expectation of the squared deviation of a random variable from its mean. It measures how far a set of numbers are spread out from their average value.

Its unit of measure corresponding to the square of the unit of measure of the variable. In this case, the variance of the temperatures is expressed in (°C)². The variance has a minimum value of 0.

Since the variance is squared, it will always have values greater than zero.

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avanturin [10]

Given:

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Domain = (-∞,∞)

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From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.

Range = All real numbers less than or equal to -4.

Range =  (-∞,-4]

Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].

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