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AleksAgata [21]
3 years ago
9

A system of linear equations includes the line that is created by the equation y = x+ 3, graphed below, and the line through the

points (3, 1) and (4, 3).
On a coordinate plane, a line goes through (0, 3) and (2, 5).
What is the solution to the system of equations?

Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

  (8, 11)

Step-by-step explanation:

The 2-point form of the equation of a line is useful for the one where only points are given.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (3 -1)/(4 -3)(x -3) +1

  y = 2(x -3) +1

We can equate this to the expression for y in the given equation.

  x +3 = 2(x -3) +1

  x +3 = 2x -5 . . . . . . eliminate parentheses

  8 = x . . . . . . . . . . . . add 5-x

Using the given equation, we can find y:

  y = x +3 = 8 +3

  y = 11

The solution to the system is (x, y) = (8, 11).

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Identify the value of y<br><br><br> (3y+5)=-4-8y+9+77
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3 years ago
Select all expressions that are equivalent to 64. 2 to the sixth power 2 to the eighth power 4 to the third power 8 squared 16 t
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Answer:

2 to the sixth, 4 to the third, 8 squared

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Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E
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Answer:

<u> x = 16</u>

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

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<u>∴ x = 16</u>

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3 years ago
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