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ipn [44]
3 years ago
8

What is the domain of the function? O x>-2 O x > 0 O x < 2 all real numbers

Mathematics
1 answer:
atroni [7]3 years ago
7 0

Answer:  x > -2, which is choice A

Notice that there's a vertical asymptote at x = -2. Think of it like an electric fence. You can get closer to it, but you can't touch it.

The domain is the set of all allowed inputs of a function.

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2r = 72 please help me
noname [10]

you divide 72 by 2 to get r by itself and get 36


so r=36

6 0
3 years ago
Read 2 more answers
A quadrilateral with at least one pair of parallel sides and at least two right angles
NemiM [27]
It could be a rhombus
4 0
3 years ago
1. Jamie purchases gifts for three friends. She chooses a book for $12.80 and then finds two identical necklaces. Her budget is
Evgen [1.6K]

Step-by-step explanation:

1.

  • (48 - 12.80)/2 = $17.6

2.

  • 250/6 ≈ 42 and more

3.

  • 485 - 319 = 166 more people

4.

  • 14.5x + 80 > 500
  • 14.5x > 420
  • x > 420/14.5
  • x > 29

5.

  • 1.25x + 3 ≤ 28
  • 1.25x ≤ 25
  • x ≤ 25/1.25
  • x ≤ 20 miles

6.  <em>This seems a typo... 460 is likely $60</em>

  • 60x + 145 ≤ 625
  • 60x ≤ 625 - 145
  • 60x ≤ 480
  • x ≤ 480/60
  • x ≤ 8 days

7 0
3 years ago
Find three right triangles based upon the Pythagorean Triple of 8, 15, and 17. Explain how you know these are triangles.
Luba_88 [7]
A^2 + b^2 = c^2
8^2 + 15^2 = 17^2
64 + 225 = 289
289=289
It is a triangle because the numbers match the Pythagorean Theorem. 
7 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
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