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3 years ago

What is the domain of the function? O x>-2 O x > 0 O x < 2 all real numbers

Mathematics

1 answer:

atroni [7]3 years ago

7 0

Answer: x > -2, which is choice A

Notice that there's a vertical asymptote at x = -2. Think of it like an electric fence. You can get closer to it, but you can't touch it.

The domain is the set of all allowed inputs of a function.

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Find the value of a and b if root3-1/root3+1+ root3+1/root3-1=a+root3 b

Digiron [165]

Answer:

a=4 and b = 0

Step-by-step explanation:

Given : $\dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b$

To find, The value of a and b

Solution,

Solving LHS of the given equation,

$\dfrac{(\sqrt 3-1)^2+(\sqrt3+1)^2}{(\sqrt 3+1)(\sqrt 3-1)}=a+\sqrt 3 b$

Since,

$(a-b)^2=a^2+b^2-2ab\\\\(a+b)^2=a^2+b^2+2ab\\\\(a-b)(a+b)=a^2+b^2$

So,

$\dfrac{3+1-2\sqrt 3+3+1+2\sqrt 3}{3-1}=a+\sqrt 3 b\\\\4=a+\sqrt 3 b$

$4+0=a+\sqrt 3 b$

On comparing we get :

a = 4 and b = 0

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3 years ago

What's 2⁄3 written as a fraction with a denominator of 9?

Naya [18.7K]

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nignag [31]

The answer would be b and c

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PLEASE HELP

stiv31 [10]

Answer:

I think it would be 34 because I divided 68.2 by 4 and got 17.05, so I multiplied that by 2, and it's closest to 34.

<em>So I think it's A.</em>

But y'all don't be mad if I'm wrong cuz I said I think.

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2 years ago