Count the number of positive integers less than 100 that do not contain any perfect square factors greater than 1.
Possible perfect squares are the squares of integers 2-9.
In fact, only squares of primes need be considered, since for example, 6^2=36 actually contains factors 2^2 and 3^2.
Tabulate the number (in [ ])of integers containing factors of
2^2=4: 4,8,12,16,...96 [24]
3^2=9: 9,18,....99 [11]
5^2=25: 25,50,75 [3]
7^2=49: 49,98 [2]
So the total number of integers from 1 to 99
N=24+11+3+2=40
=>
Number of positive square-free integers below 100 = 99-40 = 59
10 years, because In 5 years after 2008, 2013 you get new math books 5 more years you get another set of math books-2018, but 2008 plus 10 years you get science books which is also 2018 which is also when you get another set of math books. So the next year you get math books and science books shipped the same year is 2018. 2018-2008=10 so 10 years pass
Answer: A)
The first one because the x don’t repeat
Answer is <span>d. 3 + 2 = 5 and 50 ÷ 5 = 10
3 + 2 = 5
50/5 = $10</span>
Answer: 44! Hope this helps :D
Step-by-step explanation:
