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Anna71 [15]
3 years ago
12

1 point Solve using order of operations. 23.4+ (7-3) O 28

Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

Step-by-step explanation:

Do the answer is 67’949

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Answer:

S(t) = -4.9t^2 + Vot + 282.24

Step-by-step explanation:

Since the rocket is launched from the ground, So = 0 and S(t) = 0

Using s(t)=gt^2+v0t+s0 to get time t

Where g acceleration due to gravity = -4.9m/s^2. and

initial velocity = 39.2 m/a

0 = -4.9t2 + 39.2t

4.9t = 39.2

t = 8s

Substitute t in the model equation

S(t) = -49(8^2) + 3.92(8) + So

Let S(t) =0

0 = - 313.6 + 31.36 + So

So = 282.24m

The equation that can be used to model the height of the rocket after t seconds will be:

S(t) = -4.9t^2 + Vot + 282.24

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13,22,31,...<br> Find the 31st term.<br> Find the 31st term.
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Answer: 283

Step-by-step explanation:

To do this, it is helpful to get an equation you can use to solve any term.

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Answer:

11. 3^2 • 3^5 < 3^8

12. 3^3 • 3^3 > 3^5

13. Option C.

Step-by-step explanation:

11. Which of the following expressions is true?

A.  4^3• 4^4 = 412

4^3• 4^4 = 4^7 = 16384  ❌

B. 5^2 • 5^3 > 5^5

5^2 • 5^3 = 5^5 ❌

C. 3^2 • 3^5 < 3^8

3^2 • 35 = 315 ✔️

D. 5^2 • 54 = 58

5^2 • 54 = 1350 ❌

12. Which of the following expressions is true?

A. 8^3 • 8^2 < 8^4

8^3 • 8^2 = 8^5 ❌

B. 4^4 • 4^4 = 4^16

4^4 • 4^4 = 4^8 ❌

C. 2^2 • 2^6 < 2^8

2^2 • 2^6 = 2^8 ❌

D. 3^3 • 3^3 > 3^5

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