Answer:
0.005404 M
Explanation:

Since you added an excess of sodium carbonate you warrantied that all the
in the sample reacted with it. So we can say that the insoluble lead (II) carbonate
contains all the
ions in the original sample.
The moles of
are:

One mol of
is required to form one mol of
. So, the stoichiometric relationship between them is 1:1.
Knowing this, 0.00054 is also the number of moles of
in the original sample.
So, the concentration of
in the original sample is:

Answer:
no it is a ionic compound
Answer:
element is the smallest particles which cannot be broken down.