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kow [346]
3 years ago
9

The percent by mass of copper in CuBr2 is

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer: The mass percent of copper in CuBr_2 is 28.45 %.

Explanation:

In CuBr_2, there are 1 copper atom and 2 bromine atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of copper}=\frac{\text{Mass of copper}}{\text{Molar mass of copper bromide}}\times 100

Mass of copper= 63.54 g

Mass of copper bromide = 223.37 g

Putting values in above equation, we get:

\text{Mass percent of copper}=\frac{63.54}{223.37}\times 100=28.45\%

Hence, the mass percent of copper in copper bromide is 28.45 %.

Sunny_sXe [5.5K]3 years ago
4 0
Hope this helps you.

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What is the freezing point (in degrees Celcius) of 3.75 kg of water if it contains 189.9 g of C a B r 2?
blondinia [14]

Answer:

The freezing point of the solution is -1.4°C

Explanation:

Freezing point decreases by the addition of a solute to the original solvent, <em>freezing point depression formula is:</em>

ΔT = kf×m×i

<em>Where Kf is freezing point depression constant of the solvent (1.86°C/m), m is molality of the solution (Moles CaBr₂ -solute- / kg water -solvent) and i is Van't Hoff factor.</em>

Molality of the solution is:

-moles CaBr₂ (Molar mass:

189.9g ₓ (1mol / 199.89g) = 0.95 moles

Molality is:

0.95 moles CaBr₂ / 3.75kg water = <em>0.253m</em>

Van't hoff factor represents how many moles of solute are produced after the dissolution of 1 mole of solid solute, for CaBr₂:

CaBr₂(s) → Ca²⁺ + 2Br⁻

3 moles of ions are formed from 1 mole of solid solute, Van't Hoff factor is 3.

Replacing:

ΔT = kf×m×i

ΔT = 1.86°C/m×0.253m×3

ΔT = 1.4°C

The freezing point of water decreases in 1.4°C. As freezing point of water is 0°C,

<h3>The freezing point of the solution is -1.4°C</h3>

<em />

4 0
3 years ago
Read 2 more answers
How many grams of potassium bromide, KBr, are in 100mL of a 0.50 M solution?
VMariaS [17]

Answer:

5.95g

Explanation:

1 dm^{3} = 1000 mL

∴ 100 mL = 100 ÷ 1000 = 0.1 dm^{3}

Volume = <u>0.1 </u>dm^{3}<u />

Concentration = <u>0.5 M</u>

Concentration = \frac{No. of moles}{volume}

0.5 = \frac{x}{0.1}

No. of moles = 0.5 x 0.1 = <u>0.05 moles</u>

No. of moles = \frac{mass}{mass. in. 1. mole}

Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)

0.05 = \frac{x}{119}

x = 119 × 0.05 = 5.95g

4 0
3 years ago
What are the transition metals
Valentin [98]
Theyre the big bunched up group in the middle of the periodic table
8 0
3 years ago
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Suppose that CO2 in the atmosphere was held at a constant, natural level for a few thousand years. Then, CO2 was added to double
MissTica

Answer:

temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Explanation:

CO2 in the atmosphere has the property of trapping heat by absorbing it. So, with increase in the level of CO2 in the atmosphere the more heat will be absorbed by it and hence the temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Level of CO2 ∝ Temperature of the Earth

8 0
3 years ago
We can change gas to a liquid by(Increasing, decreasing, removing) the temperature and (increasing, decreasing, removing ) the p
xz_007 [3.2K]

Decreasing

Increasing

Explanation:

We can change gas to liquid by decreasing the temperature and increasing the pressure.

  • Temperature is the degree of hotness or coldness of a body.
  • It is a function of how much heat it has absorbed or lost.
  • Heat causes the thermal energy of a system to increase and the particles becomes randomized.
  • Pressure is the force per unit area of particles.
  • If we decrease the temperature of gases, they have less kinetic energy and entropy reduces.
  • The will not be random.
  • Further increasing their pressure will bring them together and make them flow like liquid.
  • This phase change is often called condensation.

learn more:

Phase change brainly.com/question/1875234

#learnwithBrainly

8 0
4 years ago
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