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kow [346]
3 years ago
9

The percent by mass of copper in CuBr2 is

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer: The mass percent of copper in CuBr_2 is 28.45 %.

Explanation:

In CuBr_2, there are 1 copper atom and 2 bromine atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of copper}=\frac{\text{Mass of copper}}{\text{Molar mass of copper bromide}}\times 100

Mass of copper= 63.54 g

Mass of copper bromide = 223.37 g

Putting values in above equation, we get:

\text{Mass percent of copper}=\frac{63.54}{223.37}\times 100=28.45\%

Hence, the mass percent of copper in copper bromide is 28.45 %.

Sunny_sXe [5.5K]3 years ago
4 0
Hope this helps you.

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Write the balanced neutralization reaction that occurs between h2so4 and koh in aqueous solution. Phases are optional.
Nutka1998 [239]

Answer:

The answer to your question is below

Explanation:

H₂SO₄ = sulphuric acid

KOH = potassium hydroxide

This is a neutralization reaction

                       H₂SO₄   +  2 KOH   ⇒     K₂SO₄   +  2H₂O

                                 2 -----------   K  ----------- 2

                                 1 -----------   S  ----------  1

                                 4 ----------   H  ---------   4

                                6 ------------   O ----------  6

4 0
3 years ago
Which one of these anions would have an "ic" ending as an acid?
GaryK [48]
The (so3)2hope this help
7 0
3 years ago
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What type of central-atom orbital hybridization corresponds to each electron-group arrangement:
galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized sp^3 orbitals → sp^3 hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

brainly.com/question/22765530

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3 0
2 years ago
Suppose of nickel(II) chloride is dissolved in of a aqueous solution of potassium carbonate. Calculate the final molarity of chl
stich3 [128]

Answer: Molarity of chloride anion = 0.32 M

<em>Note: the question is missing some values. The full question is given below;</em>

<em>Suppose 7.26 g of nickel(II) chloride is dissolved in 350 mL of a 0.50 M aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the nickel(II) chloride is dissolved in it. Be sure your answer has the correct number of significant digits.</em>

Explanation:

Molarity or molar concentration is the number of moles (mol) of component per volume (liters) concentration of solution in mol/L or M

The mass of nickel (II) chloride is 7.26 g.

The volume of potassium carbonate is 350 mL = 0.35 L

The molarity of potassium carbonate solution is 0.50 M

The reaction of nickel (II) chloride and potassium carbonate is given below.

NiCl₂(aq) + KCO₃(aq) --------> KCl(aq) +NiCO₃(s)

The dissociation of nickel (II) chloride is given below.

NiCl₂   -----> Ni²⁺ + 2Cl⁻

The molar mass of nickel (II) chloride is  129.6 g/mol

The moles of nickel (II) chloride can be calculated by the formula given below;

No of moles  = mass(g) / molar mass (g/mol)

No of moles = 7.26 / 129.6 = 0.056 moles

Therefore, molarity of NiCl₂ = 0.056 moles/ 0.35 L = 0.16 M

The molarity of 1 mole nickel (ii) chloride is 0.16 m and according to dissociation of nickel (II) chloride, 1 mole of nickel (II) chloride gives 2 moles of chloride anion.

Therefore, the molarity of chloride anion = 0.16 * 2 = 0.32 M

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3 years ago
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Jet001 [13]
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3 years ago
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