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kow [346]
3 years ago
9

The percent by mass of copper in CuBr2 is

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer: The mass percent of copper in CuBr_2 is 28.45 %.

Explanation:

In CuBr_2, there are 1 copper atom and 2 bromine atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of copper}=\frac{\text{Mass of copper}}{\text{Molar mass of copper bromide}}\times 100

Mass of copper= 63.54 g

Mass of copper bromide = 223.37 g

Putting values in above equation, we get:

\text{Mass percent of copper}=\frac{63.54}{223.37}\times 100=28.45\%

Hence, the mass percent of copper in copper bromide is 28.45 %.

Sunny_sXe [5.5K]3 years ago
4 0
Hope this helps you.

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Which of the substances are elements please help
ivanzaharov [21]

Answer:

Substances 1 and 2

Explanation:

an element only has 1 kind of atoms :3

6 0
3 years ago
A sample of Mo(NO3)6 has 2.22 x 10^22 nitrogen atom, how many oxygen atoms does the sample have?
goldfiish [28.3K]

There are 3.98 × 10^23 atoms of oxygen in the sample.

Given that;

1 mole of Mo(NO3)6 contains 6.02 × 10^23 atoms of Nitrogen

x moles of Mo(NO3)6 contains 2.22 x 10^22 atoms of nitrogen

x = 1 mole × 2.22 x 10^22 atoms/6.02 × 10^23 atoms

x = 0.0368 moles

The number of oxygen atoms in the sample is given by; 0.0368 × 6.02 × 10^23 × 18

Therefore, there are 3.98 × 10^23 atoms of oxygen in the sample.

Learn more: brainly.com/question/9743981

4 0
2 years ago
Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3
Semmy [17]

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

6 0
3 years ago
Sodium metal is sometimes used as a cooling agent in heat exchange units because of its relatively high molar heat capacity of 2
IgorC [24]

Answer:

The specific heat of sodium is 1,23J/g°C

Explanation:

Using the atomic weight of sodium (23g/mol) and the atomic weight definition, we have that each mole of the substance has 23 grams of sodium.

starting from this, we use the atomic weight of sodium to convert the units from J / mol ° C to J / g ° C

28,2 \frac{J}{mol C} x \frac{1mol}{23g} = 1,23 J/g C

4 0
3 years ago
How many moles of bromine atoms are in 2.60×10^2 grams of bromine?
AlladinOne [14]
Your answer is 3.25 moles of Bromine

4 0
4 years ago
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