Answer:
Option A. 
Step-by-step explanation:
we know that
To find the diagonal of the rectangle apply the Pythagoras Theorem
Let
D-----> the diagonal of rectangle
L----> the length of rectangle
W---> the width of rectangle
so

substitute the values



Answer:
The equivalent statement is
⇒ 2nd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- Any root can be a fraction power
- Ex: 
![\sqrt[3]{a}=a^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[4]{a}=a^{\frac{1}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
* The expression is 
∵
can be written as 
∵ ![(80)^{\frac{1}{4}}=\sqrt[4]{80}](https://tex.z-dn.net/?f=%2880%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B80%7D)
∴
= ![(\sqrt[4]{80})^{x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B80%7D%29%5E%7Bx%7D)
* The equivalent statement is ![(\sqrt[4]{80})^{x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B80%7D%29%5E%7Bx%7D)
Answer:
Length: 16m
Width: 12m
Area: 192 square meters
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
Answer:
the answers are 6.773 and 2.448