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tekilochka [14]
3 years ago
15

Justine answered 68 questions correctly on an 80-question test. Express this amount as a fraction,percent, and decimal.

Mathematics
2 answers:
vfiekz [6]3 years ago
8 0
The fraction would be 17/20. The Percent would be 85%. The Decimal would be 0.85
kenny6666 [7]3 years ago
5 0
He answered .85, 85% or 17/20 correct on the test.
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What is the answer in simplest term?
Burka [1]

Answer:

3*sqrt(3x)

--------------

2x

Step-by-step explanation:

To rationalize the denominator, we need to get rid of the square root.  We need to multiply by sqrt(12x)/sqrt(12x)

9              sqrt(12x)

----------  * -----------

sqrt(12x)      sqrt(12x)

9sqrt(12x)

-----------------

12x

We can cancel  3 in the top and bottom

3sqrt(12x)

---------------

4x

We also notice that 12 is made up of 4 and 3

3sqrt(4) sqrt(3x)

---------------

4x

3sqrt(4) sqrt(3x)

----------------------

4x

3*2sqrt(3x)

--------------

4x

We can cancel a 2 in the top and bottom

3*sqrt(3x)

--------------

2x

8 0
3 years ago
Read 2 more answers
Give three examples of equation were ther will be no solution
Luden [163]

Answer:

1. +3=5.

2. x = x + 1.

3. x = x + 1.

Step-by-step explanation:

Hope these are good! :) Have a nice day!

8 0
2 years ago
Read 2 more answers
ANYONE??
RideAnS [48]
Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height

b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²

Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²

data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft

(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.

Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³

Answer: ≈202.3 ft³
5 0
3 years ago
What is 0.4% of 1000?
alexandr1967 [171]
0.4% = 0.04 
0.04 * 1000 = 4
the answer is 4 hope I helped you out!
7 0
2 years ago
A coin is tossed 600times with the frequencies as:
brilliants [131]

Answer:

  • see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

let  \: E_1  \: and  \: E_2  \: be  \: the  \: events \:  of \:  getting  \: a  \: head

and of getting a tail respectively.

then,

1)  \: P \:  (getting \:  a  \: head) = \: P \:  (E_1)

\longrightarrow \:  \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}

\longrightarrow \:  \frac{342}{600}  =  \frac{57}{100}

\longrightarrow \: 0.57

\red{ \rule{150pt}{3pt}} \:

2) P (getting \: a\: tail) =P (E_2)

\longrightarrow \:  \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}

\longrightarrow \:  \frac{258}{600}  =  \frac{43}{100}

\longrightarrow \: 0.43

6 0
2 years ago
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